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Director
Joined: 07 Jun 2004
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A area is covered by co-ordinates (0,0) (2,0) (4,0) what is [#permalink]
17 Aug 2006, 17:52
A area is covered by co-ordinates (0,0) (2,0) (4,0)
what is the probability that a point is picked where x = y
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Senior Manager
Joined: 05 Mar 2006
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No area is covered by those coordinates. (0,0) (2,0) and (4,0) make up a line.
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VP
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rxs0005 wrote: A area is covered by co-ordinates (0,0) (2,0) (4,0)
what is the probability that a point is picked where x = y
It is the origin itself 0,0 as it is X Axis
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Manager
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(0,0), (2,0) and (4,0) are 3 points on a line segment having boundaries as (0,0) and (4,0). This line segment is on the x-axis.
In this entire line segment, the only point where x=y will be at (0,0).
Hence, number of results = 1.
However, the total number of points possible on this line segment = infinite.
Hence, the probability should be 1/infinite.
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Cheers!
Prashrash.
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CEO
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Are you sure this is the right question???
What are the choices????
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SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008
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Director
Joined: 10 Oct 2005
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prashrash wrote: (0,0), (2,0) and (4,0) are 3 points on a line segment having boundaries as (0,0) and (4,0). This line segment is on the x-axis. In this entire line segment, the only point where x=y will be at (0,0). Hence, number of results = 1. However, the total number of points possible on this line segment = infinite. Hence, the probability should be 1/infinite.
agre same reasoning
But I think it is not GMAT format question IMHO
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IE IMBA 2010
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Intern
Joined: 04 May 2006
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Doesn't matter if 3 points are on the line or not.
Anyway the answer will be P = (N)/(infinity),
where N=relatively small number
so P = 0
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VP
Joined: 25 Jun 2006
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i think he made a typo. it probably should be (0,4) to form a triangle.
If so, the probably will be the length of the line segment to the area of the triangle. It is root(2)/3, roughly about 1.142/3.
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