Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

a, b, and c are integers and a < b < c. S is the set [#permalink]
03 Jul 2005, 08:55

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 0 sessions

a, b, and c are integers and a < b < c. S is the set of all integers k such that a <= k <=b . Q is the set of all integers l such that b <= l <= c. The median of set S is (3/4)b. The median of set Q is (7/8)c. If R is the set of all integers m such that a <= m <=c, what fraction of c is the median of set R?

S = {6,7,8,9,10,11,12} Q = {12,13,14,15,16} R = {6,7,8,9,10,11,12,13,14,15,16}

The median of the above set is 11 and 11 is 11/16 of 16, so C

Plz Rthothad
can you give me a more detailled explanation
how did you find that S has an odd number of terms and which one to include in it , for Q and R as well
thanks

Plz Rthothad can you give me a more detailled explanation how did you find that S has an odd number of terms and which one to include in it , for Q and R as well thanks

regards

Mandy

Since the median of set S is 3/4b & set Q is 7/8C. Pick a number that will be divisble by 8. So I chose 16.
So let C be 16 because this one has the maximum among a,b,c.
If C is 16, set Q's median number should be 7/8 * 8 = 14.
So this is how I arrived at set Q.
Similarly, I chose 12 for b and came up with set S.
Set R includes everything from Set S & Q. After building set R one can find the median and arrive at the answer.

AJB, Do you want to wait for some participants before posting the OA

Plz Rthothad can you give me a more detailled explanation how did you find that S has an odd number of terms and which one to include in it , for Q and R as well thanks

regards

Mandy

Since the median of set S is 3/4b & set Q is 7/8C. Pick a number that will be divisble by 8. So I chose 16. So let C be 16 because this one has the maximum among a,b,c. If C is 16, set Q's median number should be 7/8 * 8 = 14. So this is how I arrived at set Q. Similarly, I chose 12 for b and came up with set S. Set R includes everything from Set S & Q. After building set R one can find the median and arrive at the answer.

AJB, Do you want to wait for some participants before posting the OA

Plz Rthothad
Thanks just a least question how did u determine A AND 6 TO BE the beggining number in set S
Thanks again,
regards

I couldn’t help myself but stay impressed. young leader who can now basically speak Chinese and handle things alone (I’m Korean Canadian by the way, so...