a, b, and c are integers and a < b < c. S is the set : Quant Question Archive [LOCKED]
Check GMAT Club App Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 07 Dec 2016, 11:19

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# a, b, and c are integers and a < b < c. S is the set

Author Message
Manager
Joined: 07 May 2007
Posts: 178
Followers: 2

Kudos [?]: 49 [0], given: 0

a, b, and c are integers and a < b < c. S is the set [#permalink]

### Show Tags

17 Jun 2007, 11:51
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

a, b, and c are integers and a < b < c. S is the set of all integers from a to b, inclusive. Q is the set of all integers from b to c, inclusive. The median of set S is (3/4)b. The median of set Q is (7/8)c. If R is the set of all integers from a to c, inclusive, what fraction of c is the median of set R?

(A) 3/8
(B) 1/2
(C) 11/16
(D) 5/7
(E) 3/4

GMAT Instructor
Joined: 04 Jul 2006
Posts: 1264
Followers: 27

Kudos [?]: 291 [0], given: 0

Re: Mean of the 3rd set [#permalink]

### Show Tags

17 Jun 2007, 14:17
iamba wrote:
a, b, and c are integers and a < b < c. S is the set of all integers from a to b, inclusive. Q is the set of all integers from b to c, inclusive. The median of set S is (3/4)b. The median of set Q is (7/8)c. If R is the set of all integers from a to c, inclusive, what fraction of c is the median of set R?

(A) 3/8
(B) 1/2
(C) 11/16
(D) 5/7
(E) 3/4

Note that for a set of consecutive integers, the median is the the average of the first and the last integer
Median of S =(a+b)/2 therefore a=b/2
Median of Q=(b+c)/2 therefore b= (3/4)c
Thus a= (3/8)c
Median of R = (a+c)/2 = (11/16)c
Director
Joined: 14 Jan 2007
Posts: 777
Followers: 2

Kudos [?]: 134 [0], given: 0

### Show Tags

17 Jun 2007, 16:25
Excellent solution by kevincan. I would guess such a question in exam.
Manager
Joined: 07 May 2007
Posts: 178
Followers: 2

Kudos [?]: 49 [0], given: 0

### Show Tags

17 Jun 2007, 17:37
Great explaination. Knowing such systematic approaches helps a lot
Manager
Joined: 28 Aug 2006
Posts: 160
Followers: 2

Kudos [?]: 15 [0], given: 0

### Show Tags

17 Jun 2007, 17:49
Good one. Excellent solution
Director
Joined: 10 Feb 2006
Posts: 657
Followers: 3

Kudos [?]: 444 [0], given: 0

### Show Tags

19 Jun 2007, 12:27
Kevin, how did you decipher that 'they were consective integers'. It didn't mention in the problem?
_________________

GMAT the final frontie!!!.

Director
Joined: 14 Jan 2007
Posts: 777
Followers: 2

Kudos [?]: 134 [0], given: 0

### Show Tags

19 Jun 2007, 13:36
Kevin, how did you decipher that 'they were consective integers'. It didn't mention in the problem?

The stem says - ALL INTEGERS between a and b. It means integers are consecutive.
Display posts from previous: Sort by