Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
MySolution Using (1) \((a+b+c+4)/4 > (a +b+c)/3\) or \(a+b+c<12\) No clue about a, b, c. Insufficient
Using (2) four possibilities: (a, b, c, 4), median (b+c)/2 < b or c < b, not possible (4, a, b, c), median (b+a)/2 < b or b > a, already known (a, 4, b, c), median (b+4)/2 < b or b > 4 (a, b, 4, c), median (b+c)/2 < b or b > 4 Considering all the above cases: \(b > 4\) But still no clue about a & c. Insufficient.
Using (1) & (2), \(b_m_i_n = 5\), (a, b, c are integers) assuming all are in A.P. which means, a = b - k c = b + k from (1), \(a+b+c < 12\) or \((b-k)+b+(b+k) < 12\) or\(3b < 12\) or \(b < 4\) but \(b > 4\) (from (2)), thus the assumption is wrong. and a, b, c cannot be in AP