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# A,B and C are positive integers. Is the multiple of them is

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VP
Joined: 08 Jun 2005
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Kudos [?]: 136 [0], given: 0

A,B and C are positive integers. Is the multiple of them is [#permalink]  23 Nov 2007, 06:36
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A,B and C are positive integers.

Is the multiple of them is dividable by 3 ?

A) A,B,C are consecutive.

B) A is dividable by 5, B is dividable by 13.

OA soon

SVP
Joined: 05 Jul 2006
Posts: 1516
Followers: 5

Kudos [?]: 124 [0], given: 39

A,B and C are positive integers.

Is the multiple of them is dividable by 3 ?

A) A,B,C are consecutive.

B) A is dividable by 5, B is dividable by 13.

a............suff

b.......insuff

Manager
Joined: 20 Jun 2007
Posts: 157
Followers: 1

Kudos [?]: 16 [0], given: 0

It looks like A

If the three positive integers are consecutive, they must include one that is divisible by 3. Therefore their product is also divisible by 3.

2 is insufficient.

If zero was defined as a positive integer, things might be different, but I think I recall reading that zero is defined as neither negative nor positive. Is this right?
VP
Joined: 08 Jun 2005
Posts: 1146
Followers: 6

Kudos [?]: 136 [0], given: 0

Raffie wrote:
It looks like A

If the three positive integers are consecutive, they must include one that is divisible by 3. Therefore their product is also divisible by 3.

2 is insufficient.

If zero was defined as a positive integer, things might be different, but I think I recall reading that zero is defined as neither negative nor positive. Is this right?

the OA is indeed A

As for your question - zero is neither negative nor positive and 0 is divisible by 3.

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