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A, B and C play cricket. A's runs are to B's runs and B's

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A, B and C play cricket. A's runs are to B's runs and B's [#permalink] New post 01 Dec 2004, 14:06
A, B and C play cricket. A's runs are to B's runs and B's runs are to C's as 3:2. They get altogether 342 runs. How many runs did A make?

(1) 162 (2) 108
(3) 72 (4) None of these
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 [#permalink] New post 01 Dec 2004, 15:39
4 .......None of these

my answer is (340* 9) /19 ...it comes approx to 162...

My assumption is that A:B = 3:2 and B:C =3:2
pLS LET ME KNOW IF IT IS CORRECT.........
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 [#permalink] New post 01 Dec 2004, 15:49
I dont understand it but this is the answer

Correct Answer - (1)

Solution:


A:B = 3:2 = 9:6;

B:C = 3:2 = 6:4 (making B equal)

Therefore, A:B:C = 9:6:4

Therefore, the runs made by A = (9/19) X 342 = 162.
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 [#permalink] New post 01 Dec 2004, 17:32
A:B:C = 9:6:4
9x+6x+4x = 19x

Runs made by A = 9x/19x*342 = 162 ans A
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 [#permalink] New post 01 Dec 2004, 17:34
gmat+obsessed wrote:
4 .......None of these

my answer is (340* 9) /19 ...it comes approx to 162...

My assumption is that A:B = 3:2 and B:C =3:2
pLS LET ME KNOW IF IT IS CORRECT.........


gmat obsessed total runs are 342 and not 340. Ans is A
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 [#permalink] New post 01 Dec 2004, 18:12
Here is my answer

A:B=3:2
A/B=3/2
A=3B/2

B:C=3:2
B/C=3/2
C=2B/3

A:B:C can be rewritten as 3B/2:B:2B/3. If we divide every term by B and multiply every term by 6 to get rid of the denominator, we get 9:6:4.

So A:B:C=9:6:4, total is 9+6+4=19

9/19 x 342=162--------answer is A
  [#permalink] 01 Dec 2004, 18:12
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A, B and C play cricket. A's runs are to B's runs and B's

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