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A, B, C, and D are integers such that A - C + B is even and

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A, B, C, and D are integers such that A - C + B is even and [#permalink] New post 20 Nov 2007, 06:13
A, B, C, and D are integers such that A - C + B is even and D + B - A is odd. Which of the following expressions is always odd?

a+d
b+d
c+d
a+b
a+c
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 [#permalink] New post 20 Nov 2007, 06:57
Expert's post
C.

1. A-C+B=(A+B)-C even
2. D+B-A =(B-A)+D odd

C and D have opposite remainders.
Therefore,
C+D = odd
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 [#permalink] New post 20 Nov 2007, 07:14
A, B, C, and D are integers such that A - C + B is even and D + B - A is odd. Which of the following expressions is always odd?

a+d
b+d
c+d
a+b
a+c

add
A - C + B +D + B - A = 2b+d-c = odd , odd = even+odd
, 2b is even thus d-c is odd ie: any summision or subtroperation ,operations of c ,d is odd.

c+d is always odd
  [#permalink] 20 Nov 2007, 07:14
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A, B, C, and D are integers such that A - C + B is even and

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