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A, B, C, and D are integers such that A - C + B is even and

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CEO
Joined: 21 Jan 2007
Posts: 2764
Location: New York City
Followers: 9

Kudos [?]: 347 [0], given: 4

A, B, C, and D are integers such that A - C + B is even and [#permalink]  20 Nov 2007, 06:13
A, B, C, and D are integers such that A - C + B is even and D + B - A is odd. Which of the following expressions is always odd?

a+d
b+d
c+d
a+b
a+c
CEO
Joined: 17 Nov 2007
Posts: 3578
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Followers: 405

Kudos [?]: 2132 [0], given: 359

[#permalink]  20 Nov 2007, 06:57
Expert's post
C.

1. A-C+B=(A+B)-C even
2. D+B-A =(B-A)+D odd

C and D have opposite remainders.
Therefore,
C+D = odd
SVP
Joined: 05 Jul 2006
Posts: 1519
Followers: 5

Kudos [?]: 111 [0], given: 39

[#permalink]  20 Nov 2007, 07:14
A, B, C, and D are integers such that A - C + B is even and D + B - A is odd. Which of the following expressions is always odd?

a+d
b+d
c+d
a+b
a+c

A - C + B +D + B - A = 2b+d-c = odd , odd = even+odd
, 2b is even thus d-c is odd ie: any summision or subtroperation ,operations of c ,d is odd.

c+d is always odd
[#permalink] 20 Nov 2007, 07:14
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A, B, C, and D are integers such that A - C + B is even and

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