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a, b, c, and d are positive integers. If the remainder is 9

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a, b, c, and d are positive integers. If the remainder is 9 [#permalink] New post 07 Jan 2013, 06:59
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a, b, c, and d are positive integers. If the remainder is 9 when a is divided by b, and the remainder is 5 when c is divided by d, which of the following is NOT a possible value for b + d?

(A) 20
(B) 19
(C) 18
(D) 16
(E) 15
[Reveal] Spoiler: OA

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Re: a, b, c, and d are positive integers. If the remainder is 9 [#permalink] New post 07 Jan 2013, 07:21
When a is divided by b remainder is 9 that means b is greater than or equals to 10, similarly d is greater than or equals to 6.
b + d cannot be 15, hence E is the answer.
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Re: a, b, c, and d are positive integers. If the remainder is 9 [#permalink] New post 09 Jan 2013, 16:12
a/b gives reminder 9, hence b\geq{10}
c/d gives reminder 5, hence d\geq{6}

Add above inequalities:
(b+d)\geq{16}

Among the answer choices, the only value that does NOT satisfy above constraint is 15.

Hence choice(E) is the answer.
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Kudos [?]: 21 [0], given: 15

Re: a, b, c, and d are positive integers. If the remainder is 9 [#permalink] New post 10 Jan 2013, 04:15
PraPon wrote:
a/b gives reminder 9, hence b\geq{10}
c/d gives reminder 5, hence d\geq{6}[/
m]

Add above inequalities:
[m](b+d)\geq{16}


Among the answer choices, the only value that does NOT satisfy above constraint is 15.

Hence choice(E) is the answer.


Hi can u please explain highlighted part? I missing sumthing here..
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Re: a, b, c, and d are positive integers. If the remainder is 9 [#permalink] New post 10 Jan 2013, 04:31
bhavinshah5685 wrote:
PraPon wrote:
a/b gives reminder 9, hence b\geq{10}
c/d gives reminder 5, hence d\geq{6}[/
m]

Add above inequalities:
[m](b+d)\geq{16}


Among the answer choices, the only value that does NOT satisfy above constraint is 15.

Hence choice(E) is the answer.


Hi can u please explain highlighted part? I missing sumthing here..


If x and y are positive integers, there exist unique integers q and r, called the quotient and remainder, respectively, such that y =divisor*quotient+remainder= xq + r and 0\leq{r}<x.

For example, when 15 is divided by 6, the quotient is 2 and the remainder is 3 since 15 = 6*2 + 3.

Notice that 0\leq{r}<x means that remainder is a non-negative integer and always less than divisor.

For more check Remainders chapter of Math Book: remainders-144665.html

a, b, c, and d are positive integers. If the remainder is 9 when a is divided by b, and the remainder is 5 when c is divided by d, which of the following is NOT a possible value for b + d?

(A) 20
(B) 19
(C) 18
(D) 16
(E) 15

According to the above, since the remainder is 9 when a is divided by b, then b (divisor) must be greater than 9 (remainder). So, the least value of b is 10.

Similarly, since he remainder is 5 when c is divided by d, then d must be greater than 5. So, the least value of d is 6.

Hence, the least value of b + d is 10 + 6 = 16. Therefore 15 (option E) is NOT a possible value for b + d.

Answer: E.

Hope it's clear.
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Re: a, b, c, and d are positive integers. If the remainder is 9   [#permalink] 10 Jan 2013, 04:31
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