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A, B, C are three taps connected to a tank such that 6 times [#permalink]
10 Nov 2010, 09:39

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Question Stats:

50% (04:03) correct
50% (03:35) wrong based on 56 sessions

A, B, C are three taps connected to a tank such that 6 times the time taken by A to fill the tank is 7 times the time taken by B and C together to fill the tank. 3 times the time taken by C to fill the tank is 10 times the time taken by A and B together to fill the tank. If A, B and C together fill the tank in 60/13 hours, then find the time taken by B alone to fill the tank?

Re: Time and Work #2 [#permalink]
10 Nov 2010, 10:23

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Expert's post

cleetus wrote:

A, B, C are three taps connected to a tank such that 6 times the time taken by A to fill the tank is 7 times the time taken by B and C together to fill the tank. 3 times the time taken by C to fill the tank is 10 times the time taken by A and B together to fill the tank. If A, B and C together fill the tank in 60/13 hours, then find the time taken by B alone to fill the tank?

Re: A, B, C are three taps connected to a tank such that 6 times [#permalink]
21 Oct 2013, 12:15

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Re: Time and Work #2 [#permalink]
23 Oct 2013, 04:35

Bunuel wrote:

cleetus wrote:

A, B, C are three taps connected to a tank such that 6 times the time taken by A to fill the tank is 7 times the time taken by B and C together to fill the tank. 3 times the time taken by C to fill the tank is 10 times the time taken by A and B together to fill the tank. If A, B and C together fill the tank in 60/13 hours, then find the time taken by B alone to fill the tank?

I have a really stupid question, but I hope you can help me out. Why isn't it 6 (1/A) = 7(1/B + 1/C) leading to a final equation of 6/7 (1/A) = 1/B + 1/C?

Re: Time and Work #2 [#permalink]
23 Oct 2013, 05:45

1

This post received KUDOS

Expert's post

pauc wrote:

Bunuel wrote:

cleetus wrote:

A, B, C are three taps connected to a tank such that 6 times the time taken by A to fill the tank is 7 times the time taken by B and C together to fill the tank. 3 times the time taken by C to fill the tank is 10 times the time taken by A and B together to fill the tank. If A, B and C together fill the tank in 60/13 hours, then find the time taken by B alone to fill the tank?

I have a really stupid question, but I hope you can help me out. Why isn't it 6 (1/A) = 7(1/B + 1/C) leading to a final equation of 6/7 (1/A) = 1/B + 1/C?

Thanks in advanced - as always!!

6 times the time taken by A to fill the tank is 7 times the time taken by B and C together to fill the tank:

Time taken by A is a. Time taken by B and C together to fill the tank is reciprocal of combined rate of B and C, thus it's bc/(b+c).

Isn't time taken by A supposed to be (1/a)? And 6 time the time taken by A in 6*(1/a) as per the R*T=W? I don't get how it's possible to say that a is the time taken by A, and then when multiplying, you do the multiplication and only then take the reciprocal.... Can you explain this please?

Isn't time taken by A supposed to be (1/a)? And 6 time the time taken by A in 6*(1/a) as per the R*T=W? I don't get how it's possible to say that a is the time taken by A, and then when multiplying, you do the multiplication and only then take the reciprocal.... Can you explain this please?

a is the time taken by A, because I denoted it that way. _________________

Isn't time taken by A supposed to be (1/a)? And 6 time the time taken by A in 6*(1/a) as per the R*T=W? I don't get how it's possible to say that a is the time taken by A, and then when multiplying, you do the multiplication and only then take the reciprocal.... Can you explain this please?

a is the time taken by A, because I denoted it that way.

If so, then why did you take the reciprocal of it for the equations? Why not leave them with a,b, and c? I am missing something, but I can't tell what....

Re: Time and Work #2 [#permalink]
13 Nov 2013, 01:10

Expert's post

ronr34 wrote:

Bunuel wrote:

ronr34 wrote:

Isn't time taken by A supposed to be (1/a)? And 6 time the time taken by A in 6*(1/a) as per the R*T=W? I don't get how it's possible to say that a is the time taken by A, and then when multiplying, you do the multiplication and only then take the reciprocal.... Can you explain this please?

a is the time taken by A, because I denoted it that way.

If so, then why did you take the reciprocal of it for the equations? Why not leave them with a,b, and c? I am missing something, but I can't tell what....

(time)*(rate)=)(job done), thus time to complete one job = reciprocal of rate. For example if 6 hours (time) are needed to complete one job --> 1/6 of the job will be done in 1 hour (rate). _________________

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