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# a, b is not equal to 0, ax^4+bx^3=5, a + b =? 1: x^4=a 2:

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a, b is not equal to 0, ax^4+bx^3=5, a + b =? 1: x^4=a 2: [#permalink]  11 Sep 2004, 23:58
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a, b is not equal to 0, ax^4+bx^3=5, a + b =?
1: x^4=a
2: x^3=b
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Joined: 22 Aug 2004
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Kudos [?]: 0 [0], given: 0

Using each condition individually a+b cannot be found out.
Using both of them together, we get ax^4+bx^3=a^2+b^2=5
Hence we can have possible values of a,b as (-1,-2), (1,2), (-1,2), (1,-2)
Then posssible values of a+b are -3,3,1,-1
Both conditions together are also Insuff
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