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A batch of cookies was divided amomg 3 tins: 2/3 of all the

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zaarathelab
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A batch of cookies was divided amomg 3 tins: 2/3 of all the [#permalink] New post   11 Nov 2009, 07:42
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A batch of cookies was divided amomg 3 tins: 2/3 of all the cookies were placed in either the blue or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin

A. 15/2
B. 9/4
C. 5/9
D. 7/5
E. 9/7
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C
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Re: A batch of cookies [#permalink] New post   11 Nov 2009, 08:19
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zaarathelab wrote:
A batch of cookies was divided amomg 3 tins: 2/3 of all the cookies were placed in either the blue or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin

A. 15/2
B. 9/4
C. 5/9
D. 7/5
E. 9/7


# of cookies - X

2/3 of all the cookies were placed in either the blue or the green tin: \(B+G=\frac{2}{3}*X\)
The rest were placed in the red tin: \(R=\frac{1}{3}*X\)
1/4 of all the cookies were placed in the blue tin: \(B=\frac{1}{4}*X\).

What fraction of the cookies that were placed in the other tins (other then blue, or in Green and Red) were placed in the green tin: \(\frac{G}{G+R}=?\)

\(B+G=\frac{2}{3}*X\) and \(B=\frac{1}{4}*X\); --> \(\frac{1}{4}*X+G=\frac{2}{3}*X\); --> \(G=\frac{5}{12}*X\).

\(\frac{G}{G+R}=(\frac{5}{12}*X)/(\frac{5}{12}*X+\frac{1}{3}*X)=\frac{5}{9}\)

Answer: C (5/9)
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Re: A batch of cookies [#permalink] New post   24 Feb 2010, 02:05
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Let Total no. of cookies = 12 (LCM(3,4))
Cookies in Blue +Green Tin = (2/3)*12 = 8
Cookies in Red Tin = 12-8 = 4
Cookies in Blue tin = (1/4)*12 = 3
Cookies in Green Tin = 8-3 = 5
Green/other(other than Blue) = 5/(4+5) = 5/9 (C)
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Re: A batch of cookies [#permalink] New post   11 Nov 2009, 08:46
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zaarathelab wrote:
A batch of cookies was divided amomg 3 tins: 2/3 of all the cookies were placed in either the blue or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin

A. 15/2
B. 9/4
C. 5/9
D. 7/5
E. 9/7



Not a clear question! How one can infer/imply "other tins" mean "green + red tins"? Is that the massage the question supplying? How "other tins" is not mean "blue + red tins"?

Just to get the idea about the question i..e. how precisely and correctly the quesion is designed? Is it a question unnecessarily designed to be a tough or is it really tough?

For me, its not a standard GMAT level question.
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Re: A batch of cookies [#permalink] New post   11 Nov 2009, 08:57
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GMAT TIGER wrote:
Not a clear question! How one can infer/imply "other tins" mean "green + red tins"? Is that the massage the question supplying? How "other tins" is not mean "blue + red tins"?

Just to get the idea about the question i..e. how precisely and correctly the quesion is designed? Is it a question unnecessarily designed to be a tough or is it really tough?

For me, its not a standard GMAT level question.


If 1/4 of all the cookies were placed in the blue tin, what fraction that were placed in the other tins were placed in the green tin?

I think that the question implies that other tins then blue, as previously the stem in the same sentence was describing the fraction in blue tin.

I don't know the source but for me this could be the GMAT question.
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Re: PS Word Problem Kaplan 600 [#permalink] New post   21 Sep 2010, 07:07
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ezinis wrote:
A batch of cookies was divided among three tins: 2/3 of all the cookies were placed in either the blue tin or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin?
A) 15/2
B) 9/4
C) 5/9
D) 7/5
E) 9/7

I was frustrated at this question by the way it worded. The OA is C, what the hell.
I got D instead. Please explain. Thanks


B + G = 2/3
R = 1 - 2/3 = 1/3
B = 1/4
So G = 2/3 - 1/4 = 5/12
G/(G+R) = G/(1-B) = (5/12)/(3/4) = 5/9
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Re: PS Word Problem Kaplan 600 [#permalink] New post   23 Sep 2010, 14:42
shrouded1 wrote:
ezinis wrote:
A batch of cookies was divided among three tins: 2/3 of all the cookies were placed in either the blue tin or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin?
A) 15/2
B) 9/4
C) 5/9
D) 7/5
E) 9/7

I was frustrated at this question by the way it worded. The OA is C, what the hell.
I got D instead. Please explain. Thanks


B + G = 2/3
R = 1 - 2/3 = 1/3
B = 1/4
So G = 2/3 - 1/4 = 5/12
G/(G+R) = G/(1-B) = (5/12)/(3/4) = 5/9



How did u assumed that it has to be G/(G+R) instead of (B+R) ?
Can you please explain ?
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Re: PS Word Problem Kaplan 600 [#permalink] New post   23 Sep 2010, 15:03
onedayill wrote:
How did u assumed that it has to be G/(G+R) instead of (B+R) ?
Can you please explain ?


The question says 1/4th were placed in the blue tin, what percentage of the ones placed in the other tins ....

So other tins ==> Green + Red
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Re: A batch of cookies was divided amomg 3 tins: 2/3 of all the [#permalink] New post   27 Mar 2016, 20:16
zaarathelab wrote:
A batch of cookies was divided amomg 3 tins: 2/3 of all the cookies were placed in either the blue or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin

A. 15/2
B. 9/4
C. 5/9
D. 7/5
E. 9/7


my approach:
say there are 12 cookies.
8 were in B and Green, and 4 were in red.
we need to put only 1/4 in blue, or 3 cookies. that leaves us with 9 remaining cookies.
since we need a fraction X/9, we can easily eliminate A, B, D, and E.
moreover, since in green tin maximum can be 9 remaining cookies, we would get 9/9, or 1.
A - 15/2 = 7.5 way more than needed.
B - 9/4 - 2.25 - no.
C - looks ok
D - >1 so no
E - > 1 so no.
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Re: A batch of cookies was divided amomg 3 tins: 2/3 of all the [#permalink] New post   04 Jul 2020, 07:39
"what fraction of the cookies that were placed in the other tins were placed in the green tin" can anyone explain this line please?
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A batch of cookies was divided amomg 3 tins: 2/3 of all the [#permalink] New post   Updated on: 06 Jul 2020, 23:17
NTA wrote:
"what fraction of the cookies that were placed in the other tins were placed in the green tin" can anyone explain this line please?

hi,
they want to say other cookies than in blue tin , means cookies from green and red tin = 4+5 = 9

Originally posted by kawal27 on 06 Jul 2020, 22:53.
Last edited by kawal27 on 06 Jul 2020, 23:17, edited 1 time in total.
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Re: A batch of cookies was divided amomg 3 tins: 2/3 of all the [#permalink] New post   06 Jul 2020, 23:01
zaarathelab wrote:
A batch of cookies was divided amomg 3 tins: 2/3 of all the cookies were placed in either the blue or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin

A. 15/2
B. 9/4
C. 5/9
D. 7/5
E. 9/7


cookies divided among 3 tins
2/3 = 8/12 = cookies place in green or blue tin.
rest means 1/3 = 4/12 place in red tin.
now if 1/4 = 3/12 cookies place in blue tin, means 8/12-3/12=5/12 place in green tin.

now other than cookies from blue tin what faction of cookies were place in green tin
means cookies from green and red tin = 5+4 =9

5 out of 9 cookies place in green tin

ANS:C
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Re: A batch of cookies was divided amomg 3 tins: 2/3 of all the [#permalink] New post   06 Jul 2020, 23:13
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NTA wrote:
"what fraction of the cookies that were placed in the other tins were placed in the green tin" can anyone explain this line please?


Question is not worded Properly and to me, it seems that it is not a standard GMAT question
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Re: A batch of cookies was divided amomg 3 tins: 2/3 of all the [#permalink] New post   24 Jan 2021, 11:17
Source - Kaplan 800

There is no error in this question.
Little grammatical confusion with if-clauses.
here,
if clauses identify the total cookies in a blue tin, the independent clause refers to the other tins or nonblue in the last sentence. if u really understand the if clauses, you will definitely understand the question.

there is no error in the question.
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A batch of cookies was divided amomg 3 tins: 2/3 of all the [#permalink] New post   24 Jan 2021, 14:01
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zaarathelab wrote:
A batch of cookies was divided among 3 tins: 2/3 of all the cookies were placed in either the blue or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin

A. 15/2
B. 9/4
C. 5/9
D. 7/5
E. 9/7


Let the total number of cookies = the LCM of the two denominators in the prompt = 12
Since 2/3 of the cookies are placed in the blue or green tin, \(B+G = \frac{2}{3} * 12 = 8\)
Since 1/4 of the cookies are placed in the blue tin, \(B = \frac{1}{4} * 12 = 3\)

What fraction of the cookies that were placed in the other tins were placed in the green tin?
other tins \(= total - B = 12-3 = 9\)
\(G = (B+G) - B = 8-3 = 5\)
\(\frac{green}{other} = \frac{5}{9}\)

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Re: A batch of cookies was divided amomg 3 tins: 2/3 of all the [#permalink] New post   01 Sep 2023, 08:49
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