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# A boat traveled upstream a distance of 90 miles at an

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Director
Joined: 11 Sep 2006
Posts: 514
Followers: 2

Kudos [?]: 35 [0], given: 0

A boat traveled upstream a distance of 90 miles at an [#permalink]  21 Oct 2006, 09:50
A boat traveled upstream a distance of 90 miles at an average speed of (v-3) miles per hour and then traveled the same distance downstream at an avg. speed of (v+3) miles per hour. If the trip upstream took 1/2 an hour longer than the trip downstream, how many hours did it take the boat to travel downstream?

2.5
2.4
2.3
2.2
2.1
_________________

...there ain't no such thing as a free lunch...

Director
Joined: 11 Sep 2006
Posts: 514
Followers: 2

Kudos [?]: 35 [0], given: 0

Anybody?? Pleeeeeeeeze?
_________________

...there ain't no such thing as a free lunch...

Manager
Joined: 22 Jul 2006
Posts: 50
Followers: 0

Kudos [?]: 1 [0], given: 0

2.5?

v-3 = 90/ t1
v+3 = 90/t2

t1-t2 = 1/2

three equations three variables
Manager
Joined: 28 Aug 2006
Posts: 160
Followers: 2

Kudos [?]: 13 [1] , given: 0

1
KUDOS

t1=0.5+t2
90/(v-3) - 90/(v+3)=0.5

v=33

Time for downstream travel is 90/(33+3) =2.5
Director
Joined: 11 Sep 2006
Posts: 514
Followers: 2

Kudos [?]: 35 [0], given: 0

OA was 2.5. Thanks!
_________________

...there ain't no such thing as a free lunch...

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