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A boat traveled upstream a distance of 90 miles at an

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Director
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A boat traveled upstream a distance of 90 miles at an [#permalink] New post 21 Oct 2006, 09:50
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A boat traveled upstream a distance of 90 miles at an average speed of (v-3) miles per hour and then traveled the same distance downstream at an avg. speed of (v+3) miles per hour. If the trip upstream took 1/2 an hour longer than the trip downstream, how many hours did it take the boat to travel downstream?

2.5
2.4
2.3
2.2
2.1
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 [#permalink] New post 22 Oct 2006, 18:32
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Answer is 2.5

t1=0.5+t2
90/(v-3) - 90/(v+3)=0.5

v=33

Time for downstream travel is 90/(33+3) =2.5
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 [#permalink] New post 22 Oct 2006, 17:38
Anybody?? Pleeeeeeeeze? :(
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 [#permalink] New post 22 Oct 2006, 18:04
2.5?

v-3 = 90/ t1
v+3 = 90/t2

t1-t2 = 1/2

three equations three variables
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 [#permalink] New post 23 Oct 2006, 06:22
OA was 2.5. Thanks!
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  [#permalink] 23 Oct 2006, 06:22
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A boat traveled upstream a distance of 90 miles at an

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