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# A bottle manufacturing company has 5 machines, each of which

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A bottle manufacturing company has 5 machines, each of which [#permalink]  23 Jan 2013, 18:22
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A bottle manufacturing company has 5 identical machines, each of which produces bottles at the same constant rate. How many bottles will all 5 machines produce running simultaneously for x hours?

(1) Running simultaneously, 3 of the machines produce 72,000 bottles in 2x hours?

(2) Running simultaneously, 2 of the machines produce 24,000 bottles in x hours?
[Reveal] Spoiler: OA

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Re: A bottle manufacturing company has 5 machines, each of which [#permalink]  23 Jan 2013, 18:58
D

Statement 1: 72000 for 2x hours...reduces to 36000 for x hours. Since rates of each machine is the same 36000/3 = 12000 bottles per machine for x hours. Therefore, 12000 x 5 = 60 000 bottles produced by 5 machines in x hourse. Sufficient.

Statement 2: If 2 of the machines working at the same rate produce 24000 bottles in x hours, that must mean 12000 bottles are produced per machine. Again, 60 000 bottles must be produced from 5 machines in x hours. Sufficient.
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Re: A bottle manufacturing company has 5 machines, each of which [#permalink]  23 Jan 2013, 19:44
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megafan wrote:
A bottle manufacturing company has 5 identical machines, each of which produces bottles at the same constant rate. How many bottles will all 5 machines produce running simultaneously for x hours?

(1) Running simultaneously, 3 of the machines produce 72,000 bottles in 2x hours?

(2) Running simultaneously, 2 of the machines produce 24,000 bottles in x hours?

Once you have the bottles produced by 1 machine in x hours, you can easily find the bottles produced by 5 machines in x hrs. Each statement independently gives you the bottles produced by 1 machine in x hrs so each statement alone is sufficient.

Though you don't need to find the actual number of bottles in this case, if you do need to in PS questions, you can use a quick one step process for such work problems. The advantage of doing it in one step is that sometimes, these fractions cancel each other out and your calculations are reduced.

Question: 3 of the machines produce 72,000 bottles in 2x hours. How many bottles will all 5 machines produce running simultaneously for x hours?

You need to find the number of bottles. So

72000 *

2x hrs becomes x hrs. The number of hrs has reduced so number of bottles made will reduce. You multiply 72000 by a number less than 1.

72000 * (1/2)

3 machines have become 5 machines. More machines will make more bottles. So multiply by 5/3, a number more than 1.

72000 * (1/2) * (5/3) = 60,000
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Senior Manager Joined: 22 Nov 2010 Posts: 288 Location: India GMAT 1: 670 Q49 V33 WE: Consulting (Telecommunications) Followers: 5 Kudos [?]: 84 [0], given: 75 Re: A bottle manufacturing company has 5 machines, each of which [#permalink] 04 Mar 2013, 01:00 megafan wrote: A bottle manufacturing company has 5 identical machines, each of which produces bottles at the same constant rate. How many bottles will all 5 machines produce running simultaneously for x hours? (1) Running simultaneously, 3 of the machines produce 72,000 bottles in 2x hours? (2) Running simultaneously, 2 of the machines produce 24,000 bottles in x hours? St 1: 3 * 2x * Rate per machine = 72000====> Rate per machine = 12000/ x Therefore, work done in x hrs by 5 machines = 12000/x * 5x = 60000 St2: Same process can be followed with this statement. therefore, D _________________ YOU CAN, IF YOU THINK YOU CAN Verbal Forum Moderator Joined: 10 Oct 2012 Posts: 630 Followers: 69 Kudos [?]: 877 [0], given: 135 Re: A bottle manufacturing company has 5 machines, each of which [#permalink] 04 Mar 2013, 01:11 Expert's post megafan wrote: A bottle manufacturing company has 5 identical machines, each of which produces bottles at the same constant rate. How many bottles will all 5 machines produce running simultaneously for x hours? (1) Running simultaneously, 3 of the machines produce 72,000 bottles in 2x hours? (2) Running simultaneously, 2 of the machines produce 24,000 bottles in x hours? Let the rate of each machine be r. Thus we have to find out the value of $$5*r*x$$. Thus, it is sufficient to find the value of$$r*x$$. F.S 1 states that $$3*r*2x$$ = 72000. No need to calculate anything, as we know the value of$$r*x$$. Sufficient. F.S 2 states that $$2*r*x$$ = 24000. Just as above, Sufficient. D. _________________ Re: A bottle manufacturing company has 5 machines, each of which [#permalink] 04 Mar 2013, 01:11 Similar topics Replies Last post Similar Topics: 15 Max has$125 consisting of bills each worth either $5 or$20 9 08 Oct 2012, 01:53
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