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A bowl was half full of water. 4 cups of water were then added to the [#permalink]
07 Jul 2011, 21:00

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A bowl was half full of water. 4 cups of water were then added to the bowl, filling the bowl to 70% of its capacity. How many cups of water are now in the bowl?

Re: A bowl was half full of water. 4 cups of water were then added to the [#permalink]
07 Jul 2011, 21:18

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enigma123 wrote:

A bowl was half full of water. 4 cups of water were then added to the bowl, filling the bowl to 70% of its capacity. How many cups of water are now in the bowl?

Ans: 14

Can someone on this forum please explain me the concept behind this question i.e. how to approach these questions? I would like to solve this using the variable i.e. x or something, if you know what I mean. Your help is very much appreciated.

Since you asked for a solution with a variable, Say cup's capacity = x Bowl's capacity = B Bowl is half full i.e. 50%B is full 50/100 * B + 4x = 70/100 * B B = 20x So Bowl's capacity is of 20 cups. If it is 70% full, it has 70/100 * 20 = 14 cups in it.

Otherwise, just think - Bowl is 50% full. It became 70% full i.e. an increase of 20% by adding 4 cups. So each cup adds 5%. 70% full will have 70/5 = 14 cups. _________________

Re: A bowl was half full of water. 4 cups of water were then added to the [#permalink]
07 Jul 2011, 21:50

Hi Karishma - Many thanks for a wonderful reply. I understand the 2nd solution. But have a minor doubt in the first solution with variable which I have highlighted:

cup's capacity = x Bowl's capacity = B Bowl is half full i.e. 50%B is full 50/100 * B + 4x = 70/100 * B B = 20x --> How did you get this? So Bowl's capacity is of 20 cups. If it is 70% full, it has 70/100 * 20 = 14 cups in it.

Apologies if I sound thick and annoying, but your help will be very much appreciated as always. _________________

Re: A bowl was half full of water. 4 cups of water were then added to the [#permalink]
07 Jul 2011, 23:39

1

This post received KUDOS

enigma123 wrote:

Hi Karishma - Many thanks for a wonderful reply. I understand the 2nd solution. But have a minor doubt in the first solution with variable which I have highlighted:

cup's capacity = x Bowl's capacity = B Bowl is half full i.e. 50%B is full 50/100 * B + 4x = 70/100 * B B = 20x --> How did you get this? So Bowl's capacity is of 20 cups. If it is 70% full, it has 70/100 * 20 = 14 cups in it.

Apologies if I sound thick and annoying, but your help will be very much appreciated as always.

Re: A bowl was half full of water. 4 cups of water were then added to the [#permalink]
20 Oct 2014, 07:45

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