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A box contains only red chips, white chips, and blue chips.

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A box contains only red chips, white chips, and blue chips. [#permalink] New post 14 Dec 2012, 04:19
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A box contains only red chips, white chips, and blue chips. If a chip is randomly selected from the box, what is the probability that the chip will be either white or blue?

(1) The probability that the chip will be blue is 1/5.
(2) The probability that the chip will be red is 1/3.
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Re: A box contains only red chips, white chips, and blue chips. [#permalink] New post 14 Dec 2012, 04:23
Expert's post
A box contains only red chips, white chips, and blue chips. If a chip is randomly selected from the box, what is the probability that the chip will be either white or blue?

The probability that the chip will be either white or blue, equals to the probability that the chip will NOT be red, thus P(white or blue)=1-P(red).

(1) The probability that the chip will be blue is 1/5. Not sufficient.

(2) The probability that the chip will be red is 1/3. P(white or blue)=1-P(red)=1-1/3=2/3. Sufficient.

Answer: B.
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Re: A box contains only red chips, white chips, and blue chips. [#permalink] New post 14 Dec 2012, 04:35
Walkabout wrote:
A box contains only red chips, white chips, and blue chips. If a chip is randomly selected from the box, what is the probability that the chip will be either white or blue?

(1) The probability that the chip will be blue is 1/5.
(2) The probability that the chip will be red is 1/3.


Too simple :)

To find : probability of white or blue (which is equivalent to 1-probability of red)

S1 : there is no probability of white -- INSUFF
S2 : red - 1/3
Therefore p(W/B) = 1-1/3 = 2/3
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Re: A box contains only red chips, white chips, and blue chips. [#permalink] New post 06 Sep 2014, 15:42
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Re: A box contains only red chips, white chips, and blue chips.   [#permalink] 06 Sep 2014, 15:42
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