Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
A business school club, Friends of Foam, is throwing a party [#permalink]
11 Jul 2005, 23:21
0% (00:00) correct
0% (00:00) wrong based on 2 sessions
This topic is locked. If you want to discuss this question please re-post it in the respective forum.
A business school club, Friends of Foam, is throwing a party at a local bar. Of the business school students at the bar, 40% are first year students and 60% are second year students. Of the first year students, 40% are drinking beer, 40% are drinking mixed drinks, and 20% are drinking both. Of the second year students, 30% are drinking beer, 30% are drinking mixed drinks, and 20% are drinking both. A business school student is chosen at random. If the student is drinking beer, what is the probability that he or she is also drinking mixed drinks?
Assume there are 100 students total.
40 First years - breaks down to:
16 first year beer drinkers
16 first year mixed drinkers
8 first year both drinkers
60 Second years:
12 drink nothing?
So there are 16+8=24 first year beer/both drinkers and
18+12=30 second year beer/both drinkers
24+30=54 out of 100 people drinking beer.
4/7 gives 57 people - this is the closest answer. I choose 4/7 or none of the above, heh.
If you assume 100 students.
For year 1, you have 16 in B, 16 in M and 8 in the intersection.
For year 2, you have 18 in B, 18 in M and 12 in the intersection.
In total, you have 34 in B, 34 in M and 20 in the intersection.
You are only talking about 48 students !
If I= B intersection M
14 in B-I, 14 in M-I and 20 in I