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A candidate who gets 20% marks fails by 10 marks but another [#permalink]
08 Jul 2005, 12:07

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Difficulty:

5% (low)

Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 0 sessions

A candidate who gets 20% marks fails by 10 marks but another candidate who gets 42% marks gets 12% more than the passing marks. Find the maximum marks.

Reason why it so is - the question asks the 'total marks' but the answer choices are expressed as %ages. That sounds wierd to me... pls. correct me if I am not getting this right...

In any case: 2 equations will be formed for this.

Assuming 't' is the total marks & 'p' being the passing marks.

(1) 0.20t = p -10
(2) 0.42t = 1.12p

Solving for t yields, t = 560/9.8 , which is approx. 57 or 58. Also, p = approx. 21.

So, the question would make more sense if it were asking "what percent of the total marks is the passing marks" - which would be 21/57*100 = 37%. Since that is nowhere near any of the choices ... I resign...

Reason why it so is - the question asks the 'total marks' but the answer choices are expressed as %ages. That sounds wierd to me... pls. correct me if I am not getting this right...

(1) 0.20t = p -10 (2) 0.42t = 1.12p

Well, 100% actually will mean 100 marks, i believe. I used your approach himjhamb, and i ended up with about 57%. However, when you backsolve (like i would have done if it were matchday), you get 100% (B) as the answer. However, i am only wondering what is the problem with our approach and why we are not getting 100%.

However, when you backsolve (like i would have done if it were matchday), you get 100% (B) as the answer. However, i am only wondering what is the problem with our approach and why we are not getting 100%.

The reason why you are getting 100% using backsolving is due to the interpretation of "but another candidate who gets 42% marks gets 12% more than the passing marks"

In my equation # 2, I have taken the above underlined part to mean 12% of passing marks & you have assumed it to be 12% of the total marks.

From my answer, passing marks = approx. 21. So, 12% more of 21 means, passing marks = 23.4 approx.... which is 42% of 57.

Now on the left hadn side we have 10 marks which indicates 10% of the total marks

This is because...the difference between the 1st and the second guys score are 22%(42 -20)...We can do this because max marks is same for both the guys

Now the second guy has 12% more than cutoff

22/100 = 12/100 + y

y = 10% = 10 marks(which the first guy fell short off)

its B). the 2nd candidate with 42 % failed by 12 %. so the passing is at 30 %. the difference between the 1st candidate with 20 % to the passing mark is 10%. so its 10%*x=10. x=100.
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If your mind can conceive it and your heart can believe it, have faith that you can achieve it.

The reason why you are getting 100% using backsolving is due to the interpretation of "but another candidate who gets 42% marks gets 12% more than the passing marks"

In my equation # 2, I have taken the above underlined part to mean 12% of passing marks & you have assumed it to be 12% of the total marks.

Thanks Christoff... it makes sense now - I think my assumption of "12% of passing marks" was incorrect... its actually, "12% of total marks".