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A candidate who gets 20% marks fails by 10 marks but another candidate

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Bunuel
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A candidate who gets 20% marks fails by 10 marks but another candidate [#permalink] New post   11 Dec 2018, 03:12
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A candidate who gets 20% marks fails by 10 marks but another candidate who gets 42% marks gets 12% more than the passing marks. Find the maximum marks.


A. 50
B. 100
C. 150
D. 200
E. 250
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abhishek911
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A candidate who gets 20% marks fails by 10 marks but another candidate [#permalink] New post   13 Aug 2019, 06:25
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Bunuel wrote:
A candidate who gets 20% marks fails by 10 marks but another candidate who gets 42% marks gets 12% more than the passing marks. Find the maximum marks.


A. 50
B. 100
C. 150
D. 200
E. 250


Bunuel

The language of the question might make the reader interpret the statements given differently.

Statement 1 -> 0.2 *(max marks) = passing marks - 10

Statement 2 - > 0.42 *(max marks) = passing marks + 0.12*(passing marks)


I think this question might need re-wording
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Re: A candidate who gets 20% marks fails by 10 marks but another candidate [#permalink] New post   13 Aug 2019, 13:55
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abhishek911 wrote:
Bunuel wrote:
A candidate who gets 20% marks fails by 10 marks but another candidate who gets 42% marks gets 12% more than the passing marks. Find the maximum marks.


A. 50
B. 100
C. 150
D. 200
E. 250


Bunuel

The language of the question might make the reader interpret the statements given differently.

Statement 1 -> 0.2 *(max marks) = passing marks - 10

Statement 2 - > 0.42 *(max marks) = passing marks + 0.12*(passing marks)


I think this question might need re-wording


Absolutely agree.
Moreover, it is clear from the question that we must take 12% from passing marks, not from max marks.
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Re: A candidate who gets 20% marks fails by 10 marks but another candidate [#permalink] New post   11 Dec 2018, 03:19
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Let the max marks be X.
Candidate gets 20% of X, but still fails by 10 marks.
0.2X + 10 = passing marks
Another candidate, 0.42X-0.12X = passing marks
0.3X = 0.2X +10
0.1X = 10
X = 100

B is the answer.
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Re: A candidate who gets 20% marks fails by 10 marks but another candidate [#permalink] New post   11 Dec 2018, 03:27
20% of max marks + 10 = passing marks
and 42% of max marks - 12% of max marks = passing marks.

Subtracting equation 1 from equation 1,

10% of max marks = 10

max marks = 100 (Option B)
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Re: A candidate who gets 20% marks fails by 10 marks but another candidate [#permalink] New post   07 Aug 2019, 12:49
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Bunuel wrote:
A candidate who gets 20% marks fails by 10 marks but another candidate who gets 42% marks gets 12% more than the passing marks. Find the maximum marks.

A. 50
B. 100
C. 150
D. 200
E. 250


given: 0.2t=p-10 and 0.42t=p+0.12t
equate: 0.2t+10=0.30t,… t=100

Answer (B).
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Re: A candidate who gets 20% marks fails by 10 marks but another candidate [#permalink] New post   06 Oct 2020, 02:17
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Let the maximum marks being 100.

20% marks fail by 10 marks: that means 20 marks out of 100 and failed by 10 marks. Hence, passing marks 30.

=> 42% marks: 42 out of 100.

Now, \(\frac{(42 - 30) }{ 30}\) * 100 = 12% increase and hence 42 marks is 12% more than passing marks [30].

Hence, the maximum marks are 100.

Answer B
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Re: A candidate who gets 20% marks fails by 10 marks but another candidate [#permalink] New post   04 Oct 2023, 18:04
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Re: A candidate who gets 20% marks fails by 10 marks but another candidate [#permalink]
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