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A car going at 40 miles per hour set out on an 80-mile trip at 9:00 A.

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Intern
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Joined: 30 Sep 2010
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A car going at 40 miles per hour set out on an 80-mile trip at 9:00 A. [#permalink]

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New post 26 Dec 2010, 08:37
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A
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Question Stats:

67% (02:20) correct 33% (00:00) wrong based on 3 sessions

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A car going at 40 miles per hour set out on an 80-mile trip at 9:00 A.M. Exactly 10 minutes later, a second car left from the same place and followed the same route. How fast, in miles per hour, was the second car going if it caught up with the first car at 10:30 A.M.?

(A) 45

(B) 50

(C) 53

(D) 55

(E) 60
[Reveal] Spoiler: OA
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Re: A car going at 40 miles per hour set out on an 80-mile trip at 9:00 A. [#permalink]

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New post 26 Dec 2010, 08:52
We know time and speed of the first car so that we can calculate Distance traveled by the first car at in 1.5 hr that is at 10:30

therefore distance traveled will be 60 miles in 90 min i.e. 1.5Hr

Now we know second car travels distance of 60 miles in 80 min (Starts 10 min after first car)

80 min = 4/3 hr
Therefore speed = distance / time
= 60 *3 /4
= 45 miles/hr

Hence "A"
Re: A car going at 40 miles per hour set out on an 80-mile trip at 9:00 A.   [#permalink] 26 Dec 2010, 08:52
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A car going at 40 miles per hour set out on an 80-mile trip at 9:00 A.

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