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A car starts 2/5 of a mile behind a bus that is traveling at [#permalink]

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02 Nov 2012, 08:33

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A car starts 2/5 of a mile behind a bus that is traveling at 60 miles per hour. If the car catches up to the bus after 2 minutes, how many miles does the car travel in that time?

A car starts 2/5 of a mile behind a bus that is traveling at 60 miles per hour. If the car catches up to the bus after 2 minutes, how many miles does the car travel in that time?

A. \(2\frac{1}{10}\)

B. \(2\frac{2}{5}\)

C. \(2\frac{1}{2}\)

D. \(2\frac{7}{8}\)

E. 3

I am not sure how to approach this one. my intuition says either B or C. please help. thank you

Car traveled the distance that the bus covered in 1/30 hours (2 minutes) plus 2/5 miles, thus \(60*\frac{1}{30}+\frac{2}{5}=2\frac{2}{5}\) miles.

Re: A car starts 2/5 of a mile behind a bus [#permalink]

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02 Nov 2012, 09:53

Bunuel wrote:

roygush wrote:

A car starts 2/5 of a mile behind a bus that is traveling at 60 miles per hour. If the car catches up to the bus after 2 minutes, how many miles does the car travel in that time?

A. \(2\frac{1}{10}\)

B. \(2\frac{2}{5}\)

C. \(2\frac{1}{2}\)

D. \(2\frac{7}{8}\)

E. 3

I am not sure how to approach this one. my intuition says either B or C. please help. thank you

Car traveled the distance that the bus covered in 1/30 hours (2 minutes) plus 2/5 miles, thus \(60*\frac{1}{30}+\frac{2}{5}=2\frac{2}{5}\) miles.

Kudos and thank you both for your help, it is clear. i knew it was easy... Bunuel, ive been going through your posts. can you please create a post with Word Problems? like tips and tricks for Work/Rate/Ratio/Precents?
_________________

A car starts 2/5 of a mile behind a bus that is traveling at 60 miles per hour. If the car catches up to the bus after 2 minutes, how many miles does the car travel in that time?

A. \(2\frac{1}{10}\)

B. \(2\frac{2}{5}\)

C. \(2\frac{1}{2}\)

D. \(2\frac{7}{8}\)

E. 3

I am not sure how to approach this one. my intuition says either B or C. please help. thank you

Car traveled the distance that the bus covered in 1/30 hours (2 minutes) plus 2/5 miles, thus \(60*\frac{1}{30}+\frac{2}{5}=2\frac{2}{5}\) miles.

Kudos and thank you both for your help, it is clear. i knew it was easy... Bunuel, ive been going through your posts. can you please create a post with Word Problems? like tips and tricks for Work/Rate/Ratio/Precents?

Re: A car starts 2/5 of a mile behind a bus [#permalink]

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02 Nov 2012, 21:31

actleader wrote:

MacFauz wrote:

My method was :

Car is travelling at a speed of 2/5 miles per 2 mins faster than the bus i.e 12 mph faster than the buse = 72 mph

So in 2 mins = 72 * 2/30 = 2.4

Answer is B.

Kudos Please... If my post helped.

Please explain your calculations...to say it rightly - formula

where did you get 12 mph and 72 mph and why did you divide it into 2/30?

Thanks for pointing it out. It was a typo.. Was thinkin 2/60(Conversion from minutes to hours since speed is in mph) equals 1/30 and typed in 2/30. I've changed that now. As for the remaining calculations. The car catches up the distance of 2/5 of a mile with the bus in 2 minutes. So the car must be travelling at a speed of 2/5 miles per 2 mins faster than the bus. 2/5 miles per 2 minutes is (2/5)*(60/2) mph. = 12 mph. Since this is the speed that the car is travelling at in excess to the speed of the bus, to get the speed of the car, we have to add this to the speed of the bus. 60 + 12 = 72

Kudos Please... If my post helped.
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Did you find this post helpful?... Please let me know through the Kudos button.

Re: A car starts 2/5 of a mile behind a bus [#permalink]

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03 Nov 2012, 07:37

MacFauz wrote:

actleader wrote:

MacFauz wrote:

My method was :

Car is travelling at a speed of 2/5 miles per 2 mins faster than the bus i.e 12 mph faster than the buse = 72 mph

So in 2 mins = 72 * 2/30 = 2.4

Answer is B.

Kudos Please... If my post helped.

Thanks for pointing it out. It was a typo.. Was thinkin 2/60(Conversion from minutes to hours since speed is in mph) equals 1/30 and typed in 2/30. I've changed that now. As for the remaining calculations. The car catches up the distance of 2/5 of a mile with the bus in 2 minutes. So the car must be travelling at a speed of 2/5 miles per 2 mins faster than the bus. 2/5 miles per 2 minutes is (2/5)*(60/2) mph. = 12 mph. Since this is the speed that the car is travelling at in excess to the speed of the bus, to get the speed of the car, we have to add this to the speed of the bus. 60 + 12 = 72

Kudos Please... If my post helped.

Now I see what (2/5)*(60/2) mph. = 12 mph means and where you got it. It is a [2][/5]/[2][/60] that represented the increasing in speed.

Re: A car starts 2/5 of a mile behind a bus that is traveling at [#permalink]

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28 Sep 2013, 02:51

Let 'x' be the speed of the CAR in miles/hour

Distance covered in catching the bus/ Relative speed of the car = Time taken (2 min)

2/(5* (x-60) = 2/60 [Since it is relative speed => x-60]

x=72 miles/hour

Distance traveled by car = Speed(x) * time(2 min)

Hence (B)
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Re: A car starts 2/5 of a mile behind a bus that is traveling at [#permalink]

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21 Oct 2013, 10:48

The bus travels at 60mph = 1 mile per minute so in 2 minutes the bus has traveled 2 miles. If the car has caught up with the bus in 2 minutes, then it has driven 2 2/5 miles since it started 2/5 miles behind the bus.

Re: A car starts 2/5 of a mile behind a bus that is traveling at [#permalink]

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21 Nov 2013, 11:20

I looked at it as a relative speed problem; both going 60 mph the car would never catch up. But in 2 minutes it traveled an extra 2/5 of a mile, so the speed it used to cover that extra 2/5 would be 30(since 30*2=60)*2/5=60/5=12mph extra, add that to the 60mph of the bus and you get 72 mph, divide by 1/30 of an hour, and you get 2.4

Re: A car starts 2/5 of a mile behind a bus that is traveling at [#permalink]

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17 Dec 2014, 09:36

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Re: A car starts 2/5 of a mile behind a bus that is traveling at [#permalink]

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24 Sep 2016, 06:02

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