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A carpenter constructed a rectangular sandbox with a [#permalink]
13 Aug 2012, 07:02
Question Stats:
74% (01:29) correct
25% (00:26) wrong based on 77 sessions
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions ProjectA carpenter constructed a rectangular sandbox with a capacity of 10 cubic feet. If the carpenter were to make a similar sandbox twice as long, twice as wide, and twice as high as the first sandbox, what would be the capacity, in cubic feet, of the second sandbox? (A) 20 (B) 40 (C) 60 (D) 80 (E) 100 Practice Questions Question: 18 Page: 154 Difficulty: 550 GMAT Club is introducing a new project: The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions ProjectEach week we'll be posting several questions from The Official Guide for GMAT® Review, 13th Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution. We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation. Thank you!
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GMAT Club team member
Joined: 02 Sep 2009
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
13 Aug 2012, 07:02
1
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Senior Manager
Joined: 15 Jun 2010
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
13 Aug 2012, 08:16
Let x,y & z be L,W & H so xyz = 10 cu ft As per question if we double the lengths on all dimensions we get (2x)(2y)(2z)=8 xyz= 8*10= 80 Answer: D
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
13 Aug 2012, 08:21
volume =l*b*h =10 cubic feet Now we have twice as long, twice as wide, and twice as high as the first sandbox, L=2*l B=2*b H=2*h final volume =L*B*H =2*l*2*b*2*h=8*(l*b*h) =8*10=80 cubic feet
answer is D
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
13 Aug 2012, 09:16
V=LWH
Original Volume = 10
In order to keep things simple. I made Height = 5, Length = 2, and Width = 1
The second statement says double everything.
Height = 10, Length = 4, and Width = 2
V = 80
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GMAT Club team member
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
17 Aug 2012, 01:02
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
12 Apr 2013, 09:52
A quick note on doubling. When you double a length you have 2*L1. When you double all lengths of a rectangle you have (2*L1)(2*L2) = A. An increase of 2^2 or 4. When you double all lengths of a rectangular prism you have (2*L1)(2*L2)(2*L3) = V. An increase of 2^3 or 8.
This leads to the basic relationship:
Line: 2*original size Rectangle: 4*original size Rectangular Prism: 8*original size
You can do the math out or memorize this relationship to speed things up.
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Re: A carpenter constructed a rectangular sandbox with a
[#permalink]
12 Apr 2013, 09:52
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