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A CEO is building an extra-wide garage in which to park his

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A CEO is building an extra-wide garage in which to park his [#permalink] New post 21 Aug 2013, 16:56
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Question Stats:

52% (02:33) correct 48% (00:53) wrong based on 21 sessions
A CEO is building an extra-wide garage in which to park his limousines. The garage is x feet wide, and at least 2 feet of space is required between each two cars and between the cars and the walls. Will all 9 limousines fit in the garage?

(1) The average width of the limousines is the square root of x.
(2) x = 100.
[Reveal] Spoiler: OA

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Re: A CEO is building an extra-wide garage in which to park his [#permalink] New post 22 Aug 2013, 01:48
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Asifpirlo wrote:
A CEO is building an extra-wide garage in which to park his limousines. The garage is x feet wide, and at least 2 feet of space is required between each two cars and between the cars and the walls. Will all 9 limousines fit in the garage?

(1) The average width of the limousines is the square root of x.
(2) x = 100.


Some assumptions to be made in this question...

When we combine we get that the width of limousines is 10 meters. Thus 9 limousines will need 9*10=90 meters, plus the additional space required between each two cars and between the cars and the walls. The sum will be more than 100 meters. So, the answer is NO. Sufficient.

Answer: C.
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Re: A CEO is building an extra-wide garage in which to park his [#permalink] New post 22 Aug 2013, 02:10
Asifpirlo wrote:
A CEO is building an extra-wide garage in which to park his limousines. The garage is x feet wide, and at least 2 feet of space is required between each two cars and between the cars and the walls. Will all 9 limousines fit in the garage?
(1) The average width of the limousines is the square root of x.
(2) x = 100.


x = 9 (Average width of Limo) + Min [10 (2)] -----(1)
10 because 9 cars will have 8 gaps & 2 gaps for extreme ends (between wall & car)

Statement 1
x = 9 \(\sqrt{x}\) + Min [10 (2)]
Still we cant solve the equation as we don't know the value of x
Thus insufficient

Statement 2
100 = 9 (Average width of Limo) + Min [10 (2)]
Still we cant solve the equation as we don't know the value of "Average width of Limo"
Thus insufficient

Statement 1&2
100 = 9 \(\sqrt{100}\) + Min [10 (2)]
100 = 9 (10) + Min [10 (2)]
100 = Min 110
This clearly shows the garage won't be able to hold all the 9 limos
Thus Sufficient

Answer C
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Re: A CEO is building an extra-wide garage in which to park his   [#permalink] 22 Aug 2013, 02:10
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