Weight of Tin - T lbs

Weight of Copper - C lbs

Weight of Lead - L lbs

T+C+L=56 lbs of the alloy

Q: Value Type

I: By weight the alloy is \(\frac{3}{7}\) lead and \(\frac{5}{14}\) copper

\(L=\frac{3}{7}*56\)

\(C=\frac{5}{14}*56\)

\(T=56-(\frac{3}{7}*56+\frac{5}{14}*56).\)

\(T=56-(\frac{11}{14}*56)\)

\(T=12 lbs\)

Statement I is Sufficient.II: By weight the alloy is 6 parts lead and 5 parts copper

Let Alloy have y parts of tin.

x be the multiplier

\(6x+5x+yx=56\)

\(11x+yx=56\)

\((11+y)x=56\)

\(y,x\) can have multiples values namely \((45, 1), (17, 2) and (3, 4).\)

Statement II is Not sufficient.Thus A is the answer. _________________

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