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# A certain basket contains 10 apples, 7 of which are red and

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Senior Manager
Joined: 23 May 2005
Posts: 266
Location: Sing/ HK
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A certain basket contains 10 apples, 7 of which are red and [#permalink]  20 Oct 2006, 01:11
A certain basket contains 10 apples, 7 of which are red and 3 of which are green. If 3 different apples are to be selected at random from the basket, what is the probability that 2 of the apples selected will be red and 1 will be green?

a. 7/40
b. 7/20
c. 49/100
d. 21/40
e. 7/10

OA is D. Can someone explain how you arrive at D? Thx
Director
Joined: 05 Feb 2006
Posts: 899
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Kudos [?]: 54 [0], given: 0

My method is to look at all the possibilities one by one:

Probability: RRG=(7/10)*(6/9)*(3/8)=7/40
Probability: GRR=(3/10)*(7/9)*(6/8)=7/40
Probability: RGR=(7/10)*(3/9)*(6/8)=7/40

(7/40)+(7/40)+(7/40)=21/40

D
Manager
Joined: 07 Jun 2006
Posts: 113
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Kudos [?]: 8 [0], given: 0

(7C2 * 3C1)/(10C3) = 63/120 = 21/40..........D
CEO
Joined: 20 Nov 2005
Posts: 2910
Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
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Kudos [?]: 132 [0], given: 0

Total cases = 10C3
Cases when 2 are red and one is green = 7C2 * 3C1

Prob = 7C2 * 3C1/ 10C3
= 21/40
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Senior Manager
Joined: 30 Aug 2006
Posts: 374
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Kudos [?]: 24 [0], given: 0

as above,

3 scenarios:

RRG,RGR,GRR

RRG=(7/10*6/9*3/8) = 7/40

others are same probability, so 7*3/40 = 21/40
Manager
Joined: 04 Oct 2006
Posts: 122
Location: Florida, Argentina, UK
Followers: 1

Kudos [?]: 2 [0], given: 0

londonluddite wrote:
as above,

3 scenarios:

RRG,RGR,GRR

RRG=(7/10*6/9*3/8) = 7/40

others are same probability, so 7*3/40 = 21/40

Perfectly explained!
)   [#permalink] 20 Oct 2006, 19:30
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