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# A certain basketball team that has played 2/3 of its games

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A certain basketball team that has played 2/3 of its games [#permalink]  04 Feb 2006, 21:24
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A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?
(A) 7
(B) 6
(C) 5
(D) 4
(E) 3

Can any one pls explain how to work out this problem??? thnks

sorry guys ! when i copy pasted it, the fractions went missing! i was in a hast that i did not notice it! i stand corrected
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vazlkaiye porkalam vazltuthan parkanum.... porkalam maralam porkalthan maruma

Last edited by razrulz on 05 Feb 2006, 06:59, edited 1 time in total.
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Missing information.. I have no idea how many games this team plays in one season. The question doesn't tells us that the team has played a certain percentage of game either...
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agree with ywilfred there is some info mising
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Fatal Error, Invalid Data: Please re enter Data ...
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the team has played 20 out of thirty games and has 17W and 3 L
the team needs 3/4W out of 30 games or 23 W
So the team needs 23-17=6 more wins
the the team can afford to lose 4 games at most of the remaining 10
Senior Manager
Joined: 11 Jan 2006
Posts: 269
Location: Chennai,India
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Kudos [?]: 3 [0], given: 0

BG wrote:
the team has played 20 out of thirty games and has 17W and 3 L
the team needs 3/4W out of 30 games or 23 W
So the team needs 23-17=6 more wins
the the team can afford to lose 4 games at most of the remaining 10

Thnks got it !
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vazlkaiye porkalam vazltuthan parkanum.... porkalam maralam porkalthan maruma

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