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A certain basketball team that has played 2/3 of its games

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A certain basketball team that has played 2/3 of its games [#permalink] New post 04 Mar 2008, 22:19
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13. A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?
(A) 7
(B) 6
(C) 5
(D) 4
(E) 3

How do you solve this in quickest way?
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Jimmy Low, Frankfurt, Germany
Blog: http://mytrainmaster.wordpress.com
GMAT Malaysia: http://gmatmalaysia.blogspot.com

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Re: 1000PS: Section 1 Question 13 [#permalink] New post 04 Mar 2008, 22:46
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jimmylow wrote:
13. A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?
(A) 7
(B) 6
(C) 5
(D) 4
(E) 3

How do you solve this in quickest way?


D.
total = 30
remaining = 10

total win = 3/4 of total = 22.5 or 23
total losses = 30 - 23 = 7 games
so max losses from the remaining 10 games = 7 - 3 = 4
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Re: 1000PS: Section 1 Question 13 [#permalink] New post 04 Mar 2008, 22:51
Thks GMAT Tiger :-D
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Jimmy Low, Frankfurt, Germany
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Re: 1000PS: Section 1 Question 13 [#permalink] New post 04 Mar 2008, 22:54
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i think it goes this way

2x/3 = 20

therefore, total number of games to be played is 30

now they want to win a minimum of 3/4. which means

30(3)/4 = 22.5 games

but since it's a minimum of 3/4 games, that would mean you need to round up, because if they win 22 games, that's less than 3/4 games. So take 23 games

Currently, they've lost 3 games, so 30 games - 3 games - x = 23

X = 4
Re: 1000PS: Section 1 Question 13   [#permalink] 04 Mar 2008, 22:54
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