A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?
So it needs to play 20 =2/3x --> 10 more games (total of 30 games).
w/30=3/4 --> 4w=90 --> w=45/2? 22.5=w.
Thus it needs to win at least 22.5-17 = 5.5 or 6. 20+6= 26 wins.
Thus it can only loose 4 more games. A total of 7.
This problem took slightly longer than 2min b/c the decimals, which I think make this problem "difficult", caught me off guard.