beatgmat wrote:

A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?

(A) 7

(B) 6

(C) 5

(D) 4

answer should be (D) 4

17 W + 3 L = 20 games

2/3 of 20 games = 30 games total

in order for the team to win at least 3/4 of the games:

3/4 * 30 = 22.5 cant have half a game so 23 to have at least 3/4

currently they have won 17 so they need 6 more wins to have 23 wins

since they have 10 games remaining, the team can only lose 4 more games.