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# A certain car averages 25 miles per gallon of gasoline when

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A certain car averages 25 miles per gallon of gasoline when [#permalink]

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25 Feb 2012, 19:00
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Difficulty:

75% (hard)

Question Stats:

56% (02:32) correct 44% (01:37) wrong based on 411 sessions

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A certain car averages 25 miles per gallon of gasoline when driven in the city and 40 miles per gallon when driven on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?

A) 28
B) 30
C) 33
D) 36
E) 38

Struggling on this one too. Any idea how to solve?
[Reveal] Spoiler: OA

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Re: Miles in a gallon [#permalink]

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25 Feb 2012, 21:55
Hi !

You need average miles/ gallon with the given data

Total Miles traveled => 10+50 = 60

City Fuel Consumption => 1 gallon - 25 miles => 10 Miles - 10/25 gallons => 0.4 gallons
Highway Fuel Consumption => 1 gallon - 40 miles => 50 Miles - 50/40 gallons => 1.25 gallons

Now the tricky part which even I got wrong in my first timed attempt

Average fuel consumption (City + Highway) = 60 miles / (0.4+1.25) = 60/1.65 = 36.6 miles / gallon

divide 60 / 15 = 40 but since 1.65 is greater than 15 the fraction has to be smaller to its either 38 / 36

38 is just too close so eliminate

Hope this helps
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Re: Miles in a gallon [#permalink]

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25 Feb 2012, 22:57
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enigma123 wrote:
A certain car averages 25 miles per gallon of gasoline when driven in the city and 40 miles per gallon when driven on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?

A)28
B)30
C)33
D)36
E)38

Struggling on this one too. Any idea how to solve?

Car averages x miles per gallon, means that 1 gallon is enough to drive x miles.

We are asked to find average miles per gallon (miles/gallon) --> average miles per gallon would be total miles driven divided by total gallons used (miles/gallon).

Total miles driven is 10+50=60.

As car averages 25 miles per gallon in the city for 10 miles in the city it will use 10/25=0.4 gallons;
As car averages 40 miles per gallon on the highway for 50 miles on the highway it will use 50/40=1.25 gallons;

So average miles per gallon equals to $$\frac{10+50}{0.4+1.25}\approx{36}$$

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Re: A certain car averages 25 miles per gallon of gasoline when [#permalink]

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07 Apr 2012, 02:39
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My take on this -

whenever I see this type of question, I make sure what the question is asking me to solve...and this makes the question easier to solve-

Here, its asking - Total distance travelled/ number of gallons used.-----------------(1)

Now start calculating individual entity.

Total distance = 50+10 = 60

Total galoons - This is the tricky part.

Generally, I solve by using unitary method.

such as - 25 miles ---- 1 gallon
1 mile = 1/25
10 miles = 1/25*10

Similarly calculate for Highway.

Try solving for highway and put the values in equation 1. You will get the answer.

Thanks
H
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Re: A certain car averages 25 miles per gallon of gasoline when [#permalink]

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26 Apr 2012, 17:51
I got Bunuel's approach.. but was wondering if weighed average should work here that is

(1*25+5*40)/6 = 37.5 ~ 38 Seems it doesnt work here.. But shouldn't it??
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Re: A certain car averages 25 miles per gallon of gasoline when [#permalink]

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26 Apr 2012, 23:09
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khushboochhabra wrote:
I got Bunuel's approach.. but was wondering if weighed average should work here that is

(1*25+5*40)/6 = 37.5 ~ 38 Seems it doesnt work here.. But shouldn't it??

Actually we are asked to find the average, but the average of miles per gallon (miles/gallon). So, you should have total miles driven in numerator and total gallons used in denominator (miles/gallon). Now, ask yourself: what do you have in numerator and denominator?
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Re: A certain car averages 25 miles per gallon of gasoline when [#permalink]

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27 Apr 2012, 06:34
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khushboochhabra wrote:
I got Bunuel's approach.. but was wondering if weighed average should work here that is

(1*25+5*40)/6 = 37.5 ~ 38 Seems it doesnt work here.. But shouldn't it??

'Distances traveled' (i.e. ratio of 1:5) cannot be the weights here to find the average mileage. The weights have to be 'number of gallons'.

If we change the question and make it:
A certain car averages 25 miles per gallon of gasoline when driven in the city and 40 miles per gallon when driven on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it uses 10 gallons in the city and then 50 gallons on the highway

Now you can use (1*25+5*40)/6

Why?

Whenever you are confused what the weights should be (e.g. here should the weights be the distance traveled or should they be gallons of fuel used...), look at the units.

Average required is $$\frac{miles}{gallon}$$. So you are trying to find the weighted average of two quantities whose units must be $$\frac{miles}{gallon}$$.

$$C_{avg} = \frac{C_1*W_1 + C_2*W_2}{{W_1 + W_2}}$$

$$C_{avg}, C_1, C_2 - \frac{miles}{gallon}$$

So $$W_1$$ and $$W_2$$ should be in gallon to get:

$$\frac{miles}{gallon} = (\frac{miles}{gallon}*gallon + \frac{miles}{gallon}*gallon)/(gallon + gallon)$$

Only if weights are in gallons, do we get 'Total miles' in the numerator and 'Total gallons' in the denominator.

We know that Average miles/gallon = Total miles/Total gallons

[highlight]Takeaway: The weights have to be the denominator units of the average.[/highlight]

So what do we do in this question?

What is the distance travelled (i.e.total miles)?
(10+50) = 60

What is the total gallons used?
Fuel used in the city = 10/25
Fuel used to go from B to C = 50/40

So Average miles/gallon = (60)/(10/25 + 50/40) = apprx 36

You need to know what the weights are going to be. Here, weights have to be the amount of fuel used i.e. in gallons because you are looking for average miles per gallon.
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Intern Joined: 28 Feb 2012 Posts: 22 GMAT 1: 700 Q48 V39 WE: Information Technology (Computer Software) Followers: 0 Kudos [?]: 10 [0], given: 3 Re: A certain car averages 25 miles per gallon of gasoline when [#permalink] ### Show Tags 27 Apr 2012, 09:59 Thanks VeritasPrepKarishma. I was having issues with understanding weights in averages. This cleared it up. Intern Joined: 06 May 2013 Posts: 24 Schools: Rotman '16 GMAT 1: 670 Q48 V33 Followers: 0 Kudos [?]: 5 [0], given: 54 Re: A certain car averages 25 miles per gallon of gasoline when [#permalink] ### Show Tags 28 Aug 2013, 01:36 I just went through this thread and I have a doubt. Applying Karishma's method of using units, in this case, we get (25*10+40*50)/(10+ 50) . The units are (miles/g * miles)/ miles = miles/gallon. Please point out the mistake in my logic. Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 6966 Location: Pune, India Followers: 2027 Kudos [?]: 12745 [3] , given: 221 Re: A certain car averages 25 miles per gallon of gasoline when [#permalink] ### Show Tags 28 Aug 2013, 04:07 3 This post received KUDOS Expert's post pjagadish27 wrote: I just went through this thread and I have a doubt. Applying Karishma's method of using units, in this case, we get (25*10+40*50)/(10+ 50) . The units are (miles/g * miles)/ miles = miles/gallon. Please point out the mistake in my logic. We need total miles in the numerator and gallons in the denominator. (C1*W1 + C2*W2) should make "miles". (W1 + W2) should make "gallons". _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

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Re: A certain car averages 25 miles per gallon of gasoline when [#permalink]

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18 Sep 2013, 11:30
enigma123 wrote:
A certain car averages 25 miles per gallon of gasoline when driven in the city and 40 miles per gallon when driven on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?

A) 28
B) 30
C) 33
D) 36
E) 38

Struggling on this one too. Any idea how to solve?

Sol:

10 miles in city while it gives 25miles/gallon in city, so 10 miles will consume : 10/25 =>2/5 gallon

10 miles on highway while it gives 40 miles/gallon on highway, so 10 miles will consume : 10/40 =>1/4 gallon

40 miles on high way whilte it gives 40 miles/gallon on highway, so 40 miles will consume: 40/40 =>1 gallon

Total gallons : 1+ (2/5)+ (1/4) = 33/20

Total distance travelled is (10+50)= 60

so avg is 60/(33/20) ==>36
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Re: A certain car averages 25 miles per gallon of gasoline when [#permalink]

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19 Sep 2013, 03:46
i took 4:37 seconds to solve this question...
Did i spend too much time ?
I actually commited a calculation mistake in between. Even if I wouldn't have done that it would take me at least 3mins.
I see the average of correct and wrond both to be 1:50 (approx)
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Re: A certain car averages 25 miles per gallon of gasoline when [#permalink]

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24 Sep 2014, 04:32
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Re: A certain car averages 25 miles per gallon of gasoline when [#permalink]

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25 Dec 2015, 08:05
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Re: A certain car averages 25 miles per gallon of gasoline when [#permalink]

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25 Dec 2015, 11:13
total miles=60
total gallons=10/25+50/40=33/20
total miles/total gallons=36.4 average mpg
Re: A certain car averages 25 miles per gallon of gasoline when   [#permalink] 25 Dec 2015, 11:13
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