Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

A certain car averages 25 miles per gallon when driving in [#permalink]

Show Tags

11 Aug 2010, 14:17

3

This post received KUDOS

5

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

95% (hard)

Question Stats:

53% (02:50) correct
47% (02:04) wrong based on 450 sessions

HideShow timer Statistics

A certain car averages 25 miles per gallon when driving in the city and 40 miles per gallon when driving on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?

A certain car averages 25 miles per gallon when driving in the city and 40 miles per gallon when driving on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?

A. 28 B. 30 C. 33 D. 36 E. 38

Car averages x miles per gallon, means that 1 gallon is enough to drive x miles.

We are asked to find average miles per gallon (miles/gallon) --> average miles per gallon would be total miles driven divided by total gallons used (miles/gallon).

Total miles driven is 10+50=60.

As car averages 25 miles per gallon in the city for 10 miles in the city it will use 10/25=0.4 gallons; As car averages 40 miles per gallon on the highway for 50 miles on the highway it will use 50/40=1.25 gallons;

So average miles per gallon equals to \(\frac{60}{0.4+1.25}\approx{36}\)

D is closest to the correct decimal answer.... the way to solve is to find out total gallons of fuel used and total distance travelled. then divide the total distance 60 miles by X gallons.

to find X: we have 2 steps - 10/25 = 0.40 gallons is for city driving; 50/40=1.25 is for highway driving.

hence final answer = 60/1.65 which comes out to be ~36mpg. hope this is clear...

For 10 miles, the fuel expended is 10/25 gallons = 0.4 gallons. Similarly for 50 miles it is 50/40 gallon = 1.25 gallons So for 60 miles total fuel spent is 1.65 gallons and hence average miles per gallon = 60/1.65 = ~36

Re: A certain car averages 25 miles per gallon when driving in [#permalink]

Show Tags

31 Dec 2012, 11:45

ketanth wrote:

why does weighted average method fail? answer is 37.5 miles/hr. Please explain

Your question on weighted avergae is not clear. You need to find out the fractions summing up to 1, thats the basic requirement, which is not applicable here. See my soln, and let me know if you have any question:

Km/Gallon Km Gallon neded City 25 10 10/25 = 2/5 Highway 40 50 50/40 = 5/4 Total 60 (8+25)/20 = 33/20

Mileage as asked = Total Km/Total Gallon = 60/(33/20) = 60*20/33 = 400/11 approx 38

Re: A certain car averages 25 miles per gallon when driving in [#permalink]

Show Tags

31 Dec 2012, 19:34

maibhihun wrote:

ketanth wrote:

why does weighted average method fail? answer is 37.5 miles/hr. Please explain

Your question on weighted avergae is not clear. You need to find out the fractions summing up to 1, thats the basic requirement, which is not applicable here. See my soln, and let me know if you have any question:

Km/Gallon Km Gallon neded City 25 10 10/25 = 2/5 Highway 40 50 50/40 = 5/4 Total 60 (8+25)/20 = 33/20

Mileage as asked = Total Km/Total Gallon = 60/(33/20) = 60*20/33 = 400/11 approx 38

Why cant we do the weighted average method: (25X10+40X50)/(50+10) = 37,5 km/gallon

I understand your logic. I am trying to understand why weighted average method logic is false.

Re: A certain car averages 25 miles per gallon when driving in [#permalink]

Show Tags

15 Aug 2013, 12:27

A certain car averages 25 miles per gallon when driving in the city and 40 miles per gallon when driving on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?

Re: A certain car averages 25 miles per gallon when driving in [#permalink]

Show Tags

15 Aug 2013, 13:21

leafsrule99 wrote:

A certain car averages 25 miles per gallon when driving in the city and 40 miles per gallon when driving on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?

A. 28 B. 30 C. 33 D. 36 E. 38

miles per gallon = 60/(10/25+50/40) = D
_________________

Re: A certain car averages 25 miles per gallon when driving in [#permalink]

Show Tags

09 Apr 2014, 12:59

ketanth wrote:

maibhihun wrote:

ketanth wrote:

why does weighted average method fail? answer is 37.5 miles/hr. Please explain

Your question on weighted avergae is not clear. You need to find out the fractions summing up to 1, thats the basic requirement, which is not applicable here. See my soln, and let me know if you have any question:

Km/Gallon Km Gallon neded City 25 10 10/25 = 2/5 Highway 40 50 50/40 = 5/4 Total 60 (8+25)/20 = 33/20

Mileage as asked = Total Km/Total Gallon = 60/(33/20) = 60*20/33 = 400/11 approx 38

Why cant we do the weighted average method: (25X10+40X50)/(50+10) = 37,5 km/gallon

I understand your logic. I am trying to understand why weighted average method logic is false.

Weighted average: (n1A1+n2A2+...nxAx)/(n1+n2+...nx) for x terms. Units of n1,n2...nx should be the same as the UNITS W.R.T. which values of A1,A2...Ax are defined as rates. E.G. If Ax represents concentration in a mixture as gm/litre, units of nx should be litre and NOT gms. In the question under consideration, we have rates defined as miles/gallon, so units of nx will be in gallons NOT miles as is give in the question. To illustrate: City journey will consume: 0.4 gallons (as calculated in earlier posts) Highway journey will consume: 1.25 gallons (''-------------""--------"") Hence by weighted average formula we have: Average consumption = (0.4*25+1.25*40)/(0.4+1.25)=60/1.65=36.363636....

Re: A certain car averages 25 miles per gallon when driving in [#permalink]

Show Tags

10 Apr 2014, 14:29

2

This post received KUDOS

ketanth wrote:

maibhihun wrote:

ketanth wrote:

why does weighted average method fail? answer is 37.5 miles/hr. Please explain

Your question on weighted avergae is not clear. You need to find out the fractions summing up to 1, thats the basic requirement, which is not applicable here. See my soln, and let me know if you have any question:

Km/Gallon Km Gallon neded City 25 10 10/25 = 2/5 Highway 40 50 50/40 = 5/4 Total 60 (8+25)/20 = 33/20

Mileage as asked = Total Km/Total Gallon = 60/(33/20) = 60*20/33 = 400/11 approx 38

Why cant we do the weighted average method: (25X10+40X50)/(50+10) = 37,5 km/gallon

I understand your logic. I am trying to understand why weighted average method logic is false.

Weighted average: (n1A1+n2A2+...nxAx)/(n1+n2+...nx) for x terms. Units of n1,n2...nx should be the same as the UNITS W.R.T. which values of A1,A2...Ax are defined as rates. E.G. If Ax represents concentration in a mixture as gm/litre, units of nx should be litre and NOT gms. In the question under consideration, we have rates defined as miles/gallon, so units of nx will be in gallons NOT miles as is give in the question. To illustrate: City journey will consume: 0.4 gallons (as calculated in earlier posts) Highway journey will consume: 1.25 gallons (''-------------""--------"") Hence by weighted average formula we have: Average consumption = (0.4*25+1.25*40)/(0.4+1.25)=60/1.65=36.363636....[/quote]

Agreed.

Or in other words, you can say that for weighted average you need to use gallons/mile as the weights are miles

so average gallons per mile would be = (10*(1/25)+ 50*(1/40))/(10+50) = (10/25+50/40)/60

To get avg. miles/gallon we need to reverse the equation and we get 60/(10/25+50/40)...same as what you calculated by 1st method.

A certain car averages 25 miles per gallon when driving in the city and 40 miles per gallon when driving on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?

A. 28 B. 30 C. 33 D. 36 E. 38

I do not understand why weighted average method fails here.

Methods don't fail. You might need to manipulate them in particular circumstances. You need to understand that whatever is given cannot be the weight. For example, when trying to find the average profit, the weight must be cost price, not number of items or selling price. Similarly, when calculating average speed, weight must be time, not distance. In the same way, here the weight must be amount of fuel used, not distance traveled. How do you figure out what the weight will be in each case? The units help you in figuring that out.

Re: A certain car averages 25 miles per gallon when driving in [#permalink]

Show Tags

09 May 2016, 11:33

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Hey, guys, So, I’ve decided to run a contest in hopes of getting the word about the site out to as many applicants as possible this application season...

Whether you’re an entrepreneur, aspiring business leader, or you just think that you may want to learn more about business, the thought of getting your Masters in Business Administration...

Term 1 has begun. If you're confused, wondering what my post on the last 2 official weeks was, that was pre-term. What that means is that the school...