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A certain car dealership has two locations. Last month, an

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A certain car dealership has two locations. Last month, an [#permalink] New post 22 Jun 2005, 16:15
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D
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A certain car dealership has two locations. Last month, an average (arithmetic mean) of 11 cars per salesperson was sold at location A and an average of 16 cars per salesperson was sold at location B. What was the average number of cars sold per salesperson at this dealership last month?

(1) Last month, the number of salespeople at location A was 3 times the number of salespeople at B.

(2) Last month, the total number of cars sold at location A was 132, and the total number of cars sold at location B was 64.
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 [#permalink] New post 22 Jun 2005, 16:24
12.25? I must be missing something, as just one of the 2 pieces of information was sufficient.
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 [#permalink] New post 22 Jun 2005, 17:31
(11x +16y) / (x+y) = Average for dealership

1)

x =3y

insufficient

2) (132 / x) = 11 ---> x = 12

(64 / y) = 16 ---- > y = 4

B = sufficient
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 [#permalink] New post 22 Jun 2005, 17:46
B....


Stmt I is insufficient as we are just given the ratio of the number of sales persons in both lot.
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 [#permalink] New post 22 Jun 2005, 17:51
Let x be the # of salespersons in Dealership A and y at B.

We need the value of (11x+16y)/x+y

S1. x=3y => We an substitute and cancel out to get the required value. Sufficient.

S2. 11x = 132, 16y = 64, enough to give us the average.

D is the answer
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Re: DS: Average Car Sales [#permalink] New post 10 Sep 2009, 18:44
This was on Kaplan. Pretty tricky; I answered B and got it wrong...

Posted from my mobile device Image
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Re: DS: Average Car Sales [#permalink] New post 10 Sep 2009, 19:41
12.25 would be correct, although it's not neccessary to find it.

1 is sufficient as follows:

Loc A: a/b = 11
Loc B: x/y = 16
Avg of both locations: (a+x)/(b+y)

With statment 1 we can substitute as follows:
Loc A: a/3y = 11
Loc B: x/y = 16
Avg of both locations: (a+x)/(3y+y)

Now a = 3y*11 = 33y
and x = 16y

Subtitute avg of both locations:
(a+x)/(3y+y) = (33y+16y)/4y = 49y/4y.
49/4 = 12.25.

Key behind this is that we have 4 variables. The numbers given (11 &
16) eliminate two of them, and statement 1 eliminates the 3rd.

[I posted this because the others who answered this put in x and y for
both dealerships, when in fact there are 4 variables, not 2]
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Re: DS: Average Car Sales [#permalink] New post 19 Sep 2009, 08:19
Case 1) Salespeople @ A = 3x, Salespeople @ B = x
Average cars sold per salesperson = [11*3x + 16*x]/[3x + x].

Sufficient

Case 2) Total cars sold @ A = 132, Total cars sold @ B = 64
# of salespeople @ A = 132/11 = 12, # of salespeople @ B = 64/16 = 4
Average cars sold per salesperson = [132 + 64]/[12 + 4].

Sufficient

Answer is D
Re: DS: Average Car Sales   [#permalink] 19 Sep 2009, 08:19
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