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A certain characteristic in a large population has a

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A certain characteristic in a large population has a [#permalink]

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18 Sep 2008, 05:16
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A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68 percent of the distribution lies within one standard deviation d of the mean, what percent of the distribution is less than m +d ?

A. 16%
B. 32%
C. 48%
D. 84%
E. 92%

OPEN DISCUSSION OF THIS QUESTION IS HERE: a-certain-characteristic-in-a-large-population-has-a-143982.html
[Reveal] Spoiler: OA
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18 Sep 2008, 05:30
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vivektripathi wrote:
A certain characteristic in a large population has a distribution that is symmetric about the
mean m. If 68 percent of the distribution lies within one standard deviation d of the mean,
what percent of the distribution is less than m +d ?
A. 16%
B. 32%
C. 48%
D. 84%
E. 92%

D

The prompt says that 68% of the population lies between m-d and m+d.

Thus, 32% of the population is less than m-d or greater than m+d.

Since the population is symmetric, half of this 32% is less than m-d and half is greater than m+d.

Thus, (68+16)% or (100-16)% of the population is less than m+d.
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18 Sep 2008, 05:37
2
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vivektripathi wrote:
A certain characteristic in a large population has a distribution that is symmetric about the
mean m. If 68 percent of the distribution lies within one standard deviation d of the mean,
what percent of the distribution is less than m +d ?
A. 16%
B. 32%
C. 48%
D. 84%
E. 92%

100-16=84%

D
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08 Jun 2013, 09:01
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zoinnk wrote:
vivektripathi wrote:
A certain characteristic in a large population has a distribution that is symmetric about the
mean m. If 68 percent of the distribution lies within one standard deviation d of the mean,
what percent of the distribution is less than m +d ?
A. 16%
B. 32%
C. 48%
D. 84%
E. 92%

D

The prompt says that 68% of the population lies between m-d and m+d.

Thus, 32% of the population is less than m-d or greater than m+d.

Since the population is symmetric, half of this 32% is less than m-d and half is greater than m+d.

Thus, (68+16)% or (100-16)% of the population is less than m+d.

Hi Team,

i think i cannot understand the language of these type of questions.
i have the problem of understanding the question language only in standard deviation and mean questions.

if anyone has like 5-10 ques for practice of this sort of questions then please post here for me. Thanks in advance!

Query : in this particular question how does the line " If 68 percent of the distribution lies within one standard deviation d of the mean" means that "The prompt says that 68% of the population lies between m-d and m+d."

Thanks a lot.
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08 Jun 2013, 10:10
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Perhaps wrote:
zoinnk wrote:
vivektripathi wrote:
A certain characteristic in a large population has a distribution that is symmetric about the
mean m. If 68 percent of the distribution lies within one standard deviation d of the mean,
what percent of the distribution is less than m +d ?
A. 16%
B. 32%
C. 48%
D. 84%
E. 92%

D

The prompt says that 68% of the population lies between m-d and m+d.

Thus, 32% of the population is less than m-d or greater than m+d.

Since the population is symmetric, half of this 32% is less than m-d and half is greater than m+d.

Thus, (68+16)% or (100-16)% of the population is less than m+d.

Hi Team,

i think i cannot understand the language of these type of questions.
i have the problem of understanding the question language only in standard deviation and mean questions.

if anyone has like 5-10 ques for practice of this sort of questions then please post here for me. Thanks in advance!

Query : in this particular question how does the line " If 68 percent of the distribution lies within one standard deviation d of the mean" means that "The prompt says that 68% of the population lies between m-d and m+d."

Thanks a lot.

A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68 percent of the distribution lies within one standard deviation d of the mean, what percent of the distribution is less than m + d ?
(A) 16%
(B) 32%
(C) 48%
(D) 84%
(E) 92%

Given that 68% lies between m-d and m+d, thus 32% lies out of this range.

Now, since the distribution is symmetric about m, then half of the 32%, so 16%, lies to the right of m+d. Therefore, 16% lies to the right of m+d, and hence 84% lies to the left of m+d, which means that 84% is less than m+d.

Similar questions to practice:
70-75-80-85-90-105-105-130-130-130-the-list-shown-consist-of-100361.html
the-standard-deviation-of-a-normal-distribution-of-data-is-99221.html
for-a-certain-exam-a-score-of-58-was-2-standard-deviations-b-128661.html
given-that-the-mean-of-set-a-is-10-what-is-the-range-of-two-141964.html

Hope it helps.

OPEN DISCUSSION OF THIS QUESTION IS HERE: a-certain-characteristic-in-a-large-population-has-a-143982.html In case of any further questions please post in this thread.
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Re: PS-Stat   [#permalink] 08 Jun 2013, 10:10
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