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A certain city owns 298 buses, whose routes are divided into [#permalink]
 21 Jun 2011, 07:03
Question Stats:
14% (02:05) correct
85% (00:50) wrong based on 21 sessions
A certain city owns 298 buses, whose routes are divided into three zones. At a given time, if q buses are in the blue zone, r buses are in the red zone, s buses are in the green zone, and t buses are in garages, how many buses are in the green zone? (1) The ratio of q to r to s is 4:6:7 and 26 buses are in garages. (2) q = 64
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My answer is A but looks like the answer choice is E. Can you please explain. The first question does provide the ratio and the total of the buses in the garage with which we can solve the equation.
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(1) One Possibility: 4x + 6x + 7x + 26 = 298 => 17x = 272 => x = 16 So # of green buses = s = 16 * 7 = 112 Other possibility - q = 4, r = 6, s = 7 So s can be 7 as well InSufficient (2) q gives us only the number of buses in blue zone, but no information about buses in grren zone Insufficient (1) + (2) q = 64, then r = 6/4 * 64 = 96, and s = 7/4 * 64 = 112 Total = 64 + 96 + 112 + 26 = 298 Sufficient Answer - C Are you sure the OA is E ?
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The OA is E but i disagree i got C as well it might be a TYPO then thanks!
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rxs0005 wrote: A certain city owns 298 buses, whose routes are divided into three zones. At a given time, if q buses are in the blue zone, r buses are in the red zone, s buses are in the green zone, and t buses are in garages, how many buses are in the green zone?
(1) The ratio of q to r to s is 4:6:7 and 26 buses are in garages.
(2) q = 64 1) This is clearly no A because we did not have proportion of the bases in guarage to other. Insuff 2) q=64 / we have no relationtion with other type 1) + 2) Give as q/s=4/7, from here 64/s=4/7. s = 64*7/4=16*7=112 my answer is C. I dont understand wy the correct answer is E Please explain somebody
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Could you please help me to understand this a little better?
Form statement A, I am not finding the second possibility suggested by subhash
There are 26 busses in the garage, so at the time of division, there are only 298-26 bussed available to be divided among the 3 regions
so x= 16. With that we can arrive at the solution? whats the catch here?
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manishgeorge wrote: Could you please help me to understand this a little better?
Form statement A, I am not finding the second possibility suggested by subhash
There are 26 busses in the garage, so at the time of division, there are only 298-26 bussed available to be divided among the 3 regions
so x= 16. With that we can arrive at the solution? whats the catch here? Answer should be "A" unless Kaplan goes like: hehe.. tricked ya!!! I didn't tell you that buses can also be in the depots and bus stations; in which case, it should be "E". 
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manishgeorge wrote: There are 26 busses in the garage, so at the time of division, there are only 298-26 bussed available to be divided among the 3 regions
so x= 16. With that we can arrive at the solution? whats the catch here? ya i thought with x=16 we can arrive at solution hence answer should be A. What's the catch?
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OA has to be A. with the 2nd option the buses don't add up to 298 unless and un till buses are somewhere else,as suggested by Fluke.
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Should be A, ratio 4:6:7 cant be reduced.
298-26= 272
272/17= 16
16*7= 112
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Should be A .
Question clearly states that q + r + s + t = 298.
Not sure why it is E :S
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Re: A certain city owns 298 buses, whose routes are divided into [#permalink]
15 Nov 2011, 14:55
I also got A. Can we confirm?
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Re: A certain city owns 298 buses, whose routes are divided into [#permalink]
15 Nov 2011, 15:48
A for me as well. Any trick involved?
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Re: A certain city owns 298 buses, whose routes are divided into
[#permalink]
15 Nov 2011, 15:48
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