132,000/11 = 12,000
What is the minimum population that the least populated district could have?
since we want the minimum we don't have to use 12,000 we can take for exsample 1,000 people from one district and move them to the other 10 districts (distributed evenly).
D1 = 12,000-1000 = 11,000
D2 = 12,000+(1000/10) = 12,100
D2/D1 = 12,100/11,000 = 121/110 = 110%
no district is to have a population that is more than 10 percent greater than the population of any other district.
the answer is (E)