Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

A certain city with population of 132,000 is to be divided [#permalink]

Show Tags

02 Mar 2009, 20:52

18

This post received KUDOS

108

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

75% (hard)

Question Stats:

54% (02:02) correct
46% (01:19) wrong based on 1457 sessions

HideShow timer Statistics

A certain city with population of 132,000 is to be divided into 11 voting districts, and no district is to have a population that is more than 10 percent greater than the population of any other district. What is the minimum possible population that the least populated district could have?

A certain city with population of 132,000 is to be divided into 11 voting districts, and no district is to have a population that is more than 10 percent greater than the population of any other district. What is the minimum possible population that the least populated district could have?

A. 10,700 B. 10,800 C. 10,900 D. 11,000 E. 11,100

As "no district is to have a population that is more than 10 percent greater than the population of any other district", then the populations of 11 districts should be in the range: \(x\) and \(1.1x\).

So we want to minimize \(x\). To minimize \(x\) we should make only one district to have that # of population (minimum possible) and the rest 10 districts to have \(1.1x\) # of population (maximum possible).

why is it that the remaining 10 popullations have all to be equal? cant you have more then two different populations?

I ask because I am having trouble getting to the equation p+10*1.1p =132

here you are stating that the 10 remaining popullations have the same popul. I am confused because I dont get why the HAVE to be the same...

The populations of 11 districts should be in the range x and 1.1x, but as we want to minimize x then all other district must have max number of population possible so 1.1x (rule: to maximize one quantity, minimize the others; to minimize one quantity, maximize the others).
_________________

Re: A certain city with population of 132,000 is to be divided [#permalink]

Show Tags

17 Apr 2012, 05:51

1

This post received KUDOS

Bunuel,

Can you tell me how you arrived at the range? x and 1.1x.

Quote:

As "no district is to have a population that is more than 10 percent greater than the population of any other district", then the populations of 11 districts should be in the range: x and 1.1x.

Can you tell me how you arrived at the range? x and 1.1x.

Quote:

As "no district is to have a population that is more than 10 percent greater than the population of any other district", then the populations of 11 districts should be in the range: x and 1.1x.

Sure. We are told that "no district has a population that is more than 10% greater than the population of ANY other district."

Now, if the least population is x then the greatest population cannot be more than 1.1x. So, all 11 districts must have population between x and 1.1x (between the least and the greatest).

Re: A certain city with population of 132,000 is to be divided [#permalink]

Show Tags

21 Sep 2012, 01:35

2

This post received KUDOS

I got this problem on my recent GMATPrep mock. This was the 8th question and I ended up getting this one wrong. This was my first mistake on the test in the quant section. I ended up getting 49Q with a total of 10 incorrect.

Coming to the problem, at the test time, I started with the below logic --:

let city 1 =x

Now city2 can have a max of 10% greater of city1 i.e., city2 = 1.1x

At this point, I guess I missed the trick and I am still trying to digest the solutions provided above.

For city3 = 10% of city2 i.e. 1.1(city2) = 1.1*1.1x = 1.21x

I lost the problem at this stage and could not proceed further. I guessed the answer choice as 10,900.

Going over the mentioned solutions, I think it makes sense to say that the sum of the other 10 would have been approximately 10*1.1x only since the value is going to increase only on the decimal side.

Thus, the equation would have indeed been x + 10(1.1x) = 132

Sometimes it is the easily worded problems which cause the most difficulty in understanding.
_________________

My attempt to capture my B-School Journey in a Blog : tranquilnomadgmat.blogspot.com

A certain city with population of 132,000 is to [#permalink]

Show Tags

31 Dec 2012, 12:19

4

This post received KUDOS

joyce wrote:

OA: D

Like any other verbose weighted avergae problem idea here is to get some idea about average and then how other data are associated wit hit. 132000 for 11 districts means an average of 12000. Now you have to find a number in 10% of this range so on lower side if N is the number than 1.1N >= 12000 or N>= 12000/1.1 i.e >=10900 so 11000 is closest to it.

Re: PS (gmatprep1) -- city population [#permalink]

Show Tags

18 May 2013, 14:11

1

This post received KUDOS

Bunuel wrote:

marijose wrote:

why is it that the remaining 10 popullations have all to be equal? cant you have more then two different populations?

I ask because I am having trouble getting to the equation p+10*1.1p =132

here you are stating that the 10 remaining popullations have the same popul. I am confused because I dont get why the HAVE to be the same...

The populations of 11 districts should be in the range x and 1.1x, but as we want to minimize x then all other district must have max number of population possible so 1.1x (rule: to maximize one quantity, minimize the others; to minimize one quantity, maximize the others).

Hi Bunuel, could u please explain the maximize rule you mentioned with a small e.g..??? also,other populations cant exceed 10 % so why are we taking the max permissible value of the population for 10 of them? pls explain

why is it that the remaining 10 popullations have all to be equal? cant you have more then two different populations?

I ask because I am having trouble getting to the equation p+10*1.1p =132

here you are stating that the 10 remaining popullations have the same popul. I am confused because I dont get why the HAVE to be the same...

The populations of 11 districts should be in the range x and 1.1x, but as we want to minimize x then all other district must have max number of population possible so 1.1x (rule: to maximize one quantity, minimize the others; to minimize one quantity, maximize the others).

Hi Bunuel, could u please explain the maximize rule you mentioned with a small e.g..??? also,other populations cant exceed 10 % so why are we taking the max permissible value of the population for 10 of them? pls explain

Sure.

Consider the following problem:

If x and y are positive integers and x+y=10, what is the maximum possible value of y?

We want to maximize y, thus we need to minimize x. Since x is a positive integer then the least value of x is 1. In this case 1+y=10 --> y=9 --> the maximum possible value of y is 9.

Next, the part saying "no district is to have a population that is more than 10 percent greater than the population of any other district" is about the maximum difference in population of districts. For example, if the least population of a district is 10 then no district can have a population more than 10+0.1*10=11.

Re: A certain city with population of 132,000 is to be divided [#permalink]

Show Tags

22 Dec 2013, 06:39

1

This post received KUDOS

1

This post was BOOKMARKED

[quote="ugimba"]A certain city with population of 132,000 is to be divided into 11 voting districts, and no district is to have a population that is more than 10 percent greater than the population of any other district. What is the minimum possible population that the least populated district could have?

A. 10,700 B. 10,800 C. 10,900 D. 11,000 E. 11,100

how do you solve this kind of problems .. any general formula(e)? I just split and try ... so usually it takes long time. Some times endup having wrong answer after somuch time spent..[/q

i approached the answer like this, 132000/11= 12000, hence the max population that each city can have is 12000. Let min. population be x. Therefore, x+10x/100=12000, which gives x as 12000/1.1 and x=10909.9. is this method right plz help

i approached the answer like this, 132000/11= 12000, hence the max population that each city can have is 12000. Let min. population be x. Therefore, x+10x/100=12000, which gives x as 12000/1.1 and x=10909.9. is this method right plz help

Re: A certain city with population of 132,000 is to be divided [#permalink]

Show Tags

17 Jun 2014, 16:58

1

This post received KUDOS

Bunuel wrote:

ENAFEX wrote:

Bunuel,

Can you tell me how you arrived at the range? x and 1.1x.

Quote:

As "no district is to have a population that is more than 10 percent greater than the population of any other district", then the populations of 11 districts should be in the range: x and 1.1x.

Sure. We are told that "no district has a population that is more than 10% greater than the population of ANY other district."

Now, if the least population is x then the greatest population cannot be more than 1.1x. So, all 11 districts must have population between x and 1.1x (between the least and the greatest).

Hope it's clear.

Hi Bunuel,

Two questions:

1)One area that stumped me was why did we want to minimize ONLY 1 and maximize 10, versus minimizing 10 and maximizing 1? In algebraic form -- why would it not be (10x + 1.1x = 132?)

2) I interpreted the 10% increase as 90% of something, meaning, I wrote, .9Y + 10Y = 132,000 and didn't get the right answer. Why is that wrong?

1)One area that stumped me was why did we want to minimize ONLY 1 and maximize 10, versus minimizing 10 and maximizing 1? In algebraic form -- why would it not be (10x + 1.1x = 132?)

2) I interpreted the 10% increase as 90% of something, meaning, I wrote, .9Y + 10Y = 132,000 and didn't get the right answer. Why is that wrong?

Thanks, R

1. If you minimize 10 and maximize 1, you'd get the maximum possible population that the most populated district could have.

General rule for such kind of problems, when the total is fixed: to maximize one quantity, minimize the others; to minimize one quantity, maximize the others.

2. a is 10% greater than b (a=1.1b --> a=11/10*b), is not the same as b is 10% less than a (b=0.9a --> a=10/9*b).

A certain city with population of 132,000 is to be divided [#permalink]

Show Tags

01 Oct 2014, 03:41

1

This post received KUDOS

Bunuel wrote:

russ9 wrote:

Hi Bunuel,

Two questions:

1)One area that stumped me was why did we want to minimize ONLY 1 and maximize 10, versus minimizing 10 and maximizing 1? In algebraic form -- why would it not be (10x + 1.1x = 132?)

2) I interpreted the 10% increase as 90% of something, meaning, I wrote, .9Y + 10Y = 132,000 and didn't get the right answer. Why is that wrong?

Thanks, R

1. If you minimize 10 and maximize 1, you'd get the maximum possible population that the most populated district could have.

General rule for such kind of problems, when the total is fixed: to maximize one quantity, minimize the others; to minimize one quantity, maximize the others.

2. a is 10% greater than b (a=1.1b --> a=11/10*b), is not the same as b is 10% less than a (b=0.9a --> a=10/9*b).

Hope this helps.

If the question had been "What is the minimum possible population that the most populated district could have?" Would that just be the average--12000?

Makes sense logically and you really cannot do \(10x + 1.1x = 132\) as that will yield a fraction of a person. A fetus?!

Re: A certain city with population of 132,000 is to be divided [#permalink]

Show Tags

07 Jun 2015, 17:23

1

This post received KUDOS

Bunuel wrote:

A certain city with population of 132,000 is to be divided into 11 voting districts, and no district is to have a population that is more than 10 percent greater than the population of any other district. What is the minimum possible population that the least populated district could have?

A. 10,700 B. 10,800 C. 10,900 D. 11,000 E. 11,100

As "no district is to have a population that is more than 10 percent greater than the population of any other district", then the populations of 11 districts should be in the range: \(x\) and \(1.1x\).

So we want to minimize \(x\). To minimize \(x\) we should make only one district to have that # of population (minimum possible) and the rest 10 districts to have \(1.1x\) # of population (maximum possible).

\(x+10*1.1x=132\) --> \(12x=132\) --> \(x=11\).

Answer: D.

Hope it's clear.

Hi Bunuel, Just one question that would help me assess if I understood the mechanics correctly... Let´s say that the question had instead asked “what is the maximum possible population that the most populated district could have?”, would the equation to solve the problem look like this?

A certain city with population of 132,000 is to be divided into 11 voting districts, and no district is to have a population that is more than 10 percent greater than the population of any other district. What is the minimum possible population that the least populated district could have?

A. 10,700 B. 10,800 C. 10,900 D. 11,000 E. 11,100

As "no district is to have a population that is more than 10 percent greater than the population of any other district", then the populations of 11 districts should be in the range: \(x\) and \(1.1x\).

So we want to minimize \(x\). To minimize \(x\) we should make only one district to have that # of population (minimum possible) and the rest 10 districts to have \(1.1x\) # of population (maximum possible).

\(x+10*1.1x=132\) --> \(12x=132\) --> \(x=11\).

Answer: D.

Hope it's clear.

Hi Bunuel, Just one question that would help me assess if I understood the mechanics correctly... Let´s say that the question had instead asked “what is the maximum possible population that the most populated district could have?”, would the equation to solve the problem look like this?

Certain Quant questions have built in shortcuts IF the answer choices are numbers and if certain other conditions are met. Here, we can TEST THE ANSWERS....

Logically, when a GMAT question asks you to figure out the LEAST or GREATEST value of something, then there are going to be restrictions on how the values will relate to one another. Here we have 11 cities; to make one as SMALL as possible, I'd think to make all of the others as LARGE as possible.

The answers: 10,700 10,800 10,900 11,000 11,100

Statistically, it's best to TEST either B or D first. D seems like an easier number to manipulate, so I'll TEST that one first.

IF the least city = 11,000 Then 10% greater would be 12,100 IF the other 10 cities are 12,100 each, then they would sum to 121,000 Add in the least city: 121,000 + 11,000 = 132,000

Since all the math that I've done matches the data that I was given....

Re: A certain city with population of 132,000 is to be divided [#permalink]

Show Tags

14 Jul 2015, 01:35

1

This post received KUDOS

Bunuel wrote:

A certain city with population of 132,000 is to be divided into 11 voting districts, and no district is to have a population that is more than 10 percent greater than the population of any other district. What is the minimum possible population that the least populated district could have?

A. 10,700 B. 10,800 C. 10,900 D. 11,000 E. 11,100

As "no district is to have a population that is more than 10 percent greater than the population of any other district", then the populations of 11 districts should be in the range: \(x\) and \(1.1x\).

So we want to minimize \(x\). To minimize \(x\) we should make only one district to have that # of population (minimum possible) and the rest 10 districts to have \(1.1x\) # of population (maximum possible).

\(x+10*1.1x=132\) --> \(12x=132\) --> \(x=11\).

Answer: D.

Hope it's clear.

Do you think that this question has no verbiage issue. How come this is possible that all districts exist that no district has population grater than 10% of any other district?
_________________

Like my post Send me a Kudos It is a Good manner. My Debrief: http://gmatclub.com/forum/how-to-score-750-and-750-i-moved-from-710-to-189016.html

gmatclubot

Re: A certain city with population of 132,000 is to be divided
[#permalink]
14 Jul 2015, 01:35

After days of waiting, sharing the tension with other applicants in forums, coming up with different theories about invites patterns, and, overall, refreshing my inbox every five minutes to...

I was totally freaking out. Apparently, most of the HBS invites were already sent and I didn’t get one. However, there are still some to come out on...

In early 2012, when I was working as a biomedical researcher at the National Institutes of Health , I decided that I wanted to get an MBA and make the...