A certain club has 10 members, including Harry. One of the

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A certain club has 10 members, including Harry. One of the [#permalink]

24 Aug 2006, 19:20

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A certain club has 10 members, including Harry. One of the 10 members is to be chosed at random to be the president, one of the remaining 9 members is to be chosed at random to be the secretary, and one of the remaining 8 members is to be chosen at random to be the treasurer. What is the probability that Harry will either be the secretary or the member chosen to be the treasurer?

A 1/720
B 1/80
C 1/10
D 1/9
E 1/5

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24 Aug 2006, 23:41

E

p(H as secretary) = 9/10 * 1/9 = 1/10
p(H as treasurer) = 9/10 * 8/9 * 1/8 = 1/10

p(H as secretary or treasurer) = 1/10 + 1/10 = 1/5

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26 Aug 2006, 07:57

Total permutations = 10P3 = 10!/7!

Permutations when Harry is Sec = 9P2
Permutations when Harry is Trea = 9P2

Required Prob. = 2. (9!/7!)/(10!/7!) = 2/10 = 1/5

[#permalink] 26 Aug 2006, 07:57

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A certain club has 10 members, including Harry. One of the

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