A certain club has 20 members. What is the ratio of the

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A certain club has 20 members. What is the ratio of the [#permalink]

23 Jan 2008, 03:39

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A certain club has 20 members. What is the ratio of the member of 5-member
committees that can be formed from the members of the club to the number of 4-member
committees that can be formed from the members of the club?

A. 16 to 1
B. 15 to 1
C. 16 to 5
D. 15 to 6
E. 5 to 4

Please Explain, OA will follow

Director

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Re: PS Set #22 [#permalink]

23 Jan 2008, 05:46

I think it is C,

16 to 5

I used combinations and the ratio would be ->

(20!/(5! X 15!)) / (20!/(4! X 16!)) => (16! X 4!)/(15! X 5!) =>16/5
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Re: PS Set #22 [#permalink]

23 Jan 2008, 05:50

$formdata=20C5+$ : $formdata=20C4$

$formdata=20C5+=+\frac{20!}{15!5!}+=+\frac{20*19*18*17*16}{5*4*3*2*1}+=+\frac{19*3*17*16}{1}$

$formdata=20C4+=+\frac{20!}{16!4!}+=+\frac{20*19*18*17}{4*3*2*1}+=+\frac{5*19*3*17}{1}$

$formdata=\frac{19*3*17*16}{5*19*3*17}+=+\frac{16}{5}$

Answer C

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Re: PS Set #22 [#permalink]

23 Jan 2008, 13:24

C too because of the same reasons.

Manager

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Re: PS Set #22 [#permalink]

25 Jan 2008, 11:40

Sorry for thh late reply. OA is C
tnx

Re: PS Set #22 [#permalink] 25 Jan 2008, 11:40

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A certain club has 20 members. What is the ratio of the

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