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A certain company assigns employees to offices in such a way [#permalink]
 08 Jan 2010, 14:18
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58% (01:00) wrong based on 1 sessions
A certain company assigns employees to offices in such a way that some of the offices can be empty and more than one employee can be assigned to an office. In how many ways can the company assign 3 employees to 2 different offices? A. 5 B. 6 C. 7 D. 8 E. 9
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Re: A certain company [#permalink]
08 Jan 2010, 16:58
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Re: A certain company [#permalink]
09 Jan 2010, 03:27
i am still not able to understand. Can you please explain in detail?
also please tell me where i went wrong.This was my logic.
No. of people
office 1: 0|0|0|1|1|1|2|2|3
office 2: 1|2|3|0|1|2|0|1|0
this gives me 9 possible combination
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Re: A certain company [#permalink]
09 Jan 2010, 04:25
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sagarsabnis wrote: i am still not able to understand. Can you please explain in detail?
also please tell me where i went wrong.This was my logic.
No. of people
office 1: 0|0|0|1|1|1|2|2|3
office 2: 1|2|3|0|1|2|0|1|0
this gives me 9 possible combination First of all you should assign ALL 3 employees to either of the offices. You can have the following scenarios: No. of people A|B|C|D| office 1: 0|1|2|3| office 2: 3|2|1|0| In scenario (A) and (D) there is only one way to assign three people. But in (B) and (C) there will be 3 cases in each: Let's say there are 3 employees: Tom, Mary and Kate. In (B): Tom can be in office #1 and Mary/Kate in #2 OR Mary can be in #1 and Tom/Kate in #2 OR Kate in #1 and Tom/Mary in #2. Total 3 cases for (B). The same for (C). (A)+(B)+(C)+(D)=1+3+3+1=8. The way I solved this was different: Each of the three employees, Tom, Mary and Kate, has two choices office #1 or office #2. Hence total # of combinations (assignments) is 2*2*2=2^3=8. Hope it's clear.
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A certain company employee [#permalink]
25 Oct 2010, 03:52
A certain company assigns employees to offices in such a way that some of the offices can be empty and more than one employee can be assigned to an office, In how many ways can the company assign 3 employees to 2 different offices? A) 5 B) 6 C) 7 D) 8 E) 9
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Re: A certain company employee [#permalink]
25 Oct 2010, 04:26
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Two offices can be filled in two ways, when all the three employee will be in same room or when two employee in one room and one in other room.
when all the three employee will be in same = 3C3 * 2! =2 (2!, because any of the room can be taken)
when two employee in one room and one in other room. = 3C2 * 1C1 * 2! = 6
Hence total ways = 6+2
Answer is 8.
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Last edited by ankitranjan on 25 Oct 2010, 04:43, edited 1 time in total.
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Re: A certain company employee [#permalink]
25 Oct 2010, 04:38
monirjewel wrote: A certain company assigns employees to offices in such a way that some of the offices can be empty and more than one employee can be assigned to an office, In how many ways can the company assign 3 employees to 2 different offices?
A) 5
B) 6
C) 7
D) 8
E) 9 Every employee has got the possibilit of getting assigned to any of the two offices. Hence total possibilities = 2^3 = 8
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Re: Why D any not B? please help me out [#permalink]
17 Nov 2010, 08:56
SoniaSaini wrote: A certain company assigns employees to offices in such a way that some of the offices can be empty and more than one employee can be assigned to an office. In how many ways can the company assign 3 employees to 2 different offices?
A. 5
B. 6
C. 7
D. 8
E. 9
thanks in advance!!! For each one of the 3 employees, there are two choices. He can be allotted to any one of the two offices. Hence total number ways will be 2 * 2* 2 = 8 ways
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Re: A certain company [#permalink]
21 Nov 2010, 07:12
The best way to remember this is :
(Decisions) ^ (Players)
For this problem - 2 decisions , 3 players : 2^3=8
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Specific GMAT Question [#permalink]
01 Oct 2012, 13:04
A certain company assigns employees to offices in such a way that some of the offices can be empty and more than one employee can be assigned to an office. In how many ways can the company assign 3 employees to 2 different offices?
A. 5
B. 6
C. 7
D. 8
E. 9
So my approach to this question was just to count how many ways you can arrange three employees among two offices (some can be empty), so:
3 emp in an off and 0 in the other, 2 and 1, 1 and 2, then 0 and 3.
I only counted 4 arrangements, obviously that's not the answer. How do I do this problem?
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Re: Specific GMAT Question [#permalink]
01 Oct 2012, 13:13
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Re: Specific GMAT Question [#permalink]
02 Oct 2012, 02:00
GmatGuy786 wrote: A certain company assigns employees to offices in such a way that some of the offices can be empty and more than one employee can be assigned to an office. In how many ways can the company assign 3 employees to 2 different offices?
A. 5
B. 6
C. 7
D. 8
E. 9
So my approach to this question was just to count how many ways you can arrange three employees among two offices (some can be empty), so:
3 emp in an off and 0 in the other, 2 and 1, 1 and 2, then 0 and 3.
I only counted 4 arrangements, obviously that's not the answer. How do I do this problem? Merging similar topics. Please refer to the solutions above.
_________________
PLEASE READ AND FOLLOW: 11 Rules for Posting!!!
RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory
COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. NEW!!!
DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set. NEW!!!
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Re: Specific GMAT Question
[#permalink]
02 Oct 2012, 02:00
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