A certain company's customer service department has five : PS Archive
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# A certain company's customer service department has five

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Director
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A certain company's customer service department has five [#permalink]

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12 Oct 2005, 20:26
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A certain company's customer service department has five employees. The hourly wage for each employee ranges from $5 an hour to$20 an hour. Which of the following could be the average (arithmetic mean) hourly wage for the customer service employees?

1) $7.50 an hour 2)$9 an hour
3) $16.75 an hour A. 1 only B. 2 only C. 3 only D. 1 and 2 only E. 2 and 3 only _________________ Cheers, Rahul. Director Joined: 21 Aug 2005 Posts: 793 Followers: 2 Kudos [?]: 24 [0], given: 0 ### Show Tags 12 Oct 2005, 20:33 E (2 & 3 only) Avg. can range b/w 1. Max 17 with wages 20, 20, 20, 20, 5 2. Min 8 with wages 5, 5, 5, 5, 20 Senior Manager Joined: 11 May 2004 Posts: 458 Location: New York Followers: 1 Kudos [?]: 47 [0], given: 0 ### Show Tags 13 Oct 2005, 06:14 Not sure if I am reading the question correctly, but is it possible for the wages to be another value other than$5 or $20? Also, can we have a wage as$7.5?
Manager
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15 Oct 2005, 08:04
am still nt getting this...
the avg can range max from 20,20,20,20,19 = avg 19.9 & min 5,5,5,5,6 = avg 5.2...I see all 3 as a possibility
Senior Manager
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15 Oct 2005, 10:21
desiguy wrote:
Not sure if I am reading the question correctly, but is it possible for the wages to be another value other than $5 or$20? Also, can we have a wage as \$7.5?

Yes it is possible. However atleast one wage has to be 5 and other has to be 20. Hence it adheres to range of 5 to 20.
Senior Manager
Joined: 02 Oct 2005
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15 Oct 2005, 10:23
sushom101 wrote:
am still nt getting this...
the avg can range max from 20,20,20,20,19 = avg 19.9 & min 5,5,5,5,6 = avg 5.2...I see all 3 as a possibility

The question has given the range from 5 to 20. Hence atleast one's salary should be 5 and other should be 20. With this you would be able to calculate the min and max range of arithmetic mean and choose the answer.

Please refer to gsr/Himalaya's post as well.
15 Oct 2005, 10:23
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