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A certain cube floating in a bucket of water has between 80 [#permalink]
06 Sep 2004, 17:58

6

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

75% (hard)

Question Stats:

61% (02:53) correct
39% (02:07) wrong based on 389 sessions

A certain cube floating in a bucket of water has between 80 and 85 percent of its volume below the surface of the water. If between 12 and 16 cubic centimeters of the cube's volume is above the surface of the water, then the length of a side of the cube is approximately

Best way to approach this problem is to plug in the answers since the
answers give us the side of the cube.

If we start with the middle choice, C, then we have a cube with
side 7. If the cube has a side of 7 then it will have a volume of 343. We are told that between 80 and 85% of the volume is below the surface of the water, which means that between 15 and 20% of the volume is above the surface.

If the volume of the cube is 343 then 20% is about 68 and 15% is about
51. Neither of these numbers is between the 12 and 16 cubic centimeters that are supposed to be above water, so clearly this canâ€™t be the answer.

Since the numbers are too large with need to trysomething smaller. Pick one of the smaller choices and try again. Then you'll find it

I can see by the number of good answers to my several daily problems that everybody is sharp and ready for the GMAT

Re: A certain cube floating in a bucket of water has between 80 [#permalink]
15 Mar 2012, 03:59

6

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Expert's post

2

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Antmavel wrote:

A certain cube floating in a bucket of water has between 80 and 85 percent of its volume below the surface of the water. If between 12 and 16 cubic centimeters of the cube's volume is above the surface of the water, then the length of a side of the cube is approximately

A. 4 B. 5 C. 7 D. 8 E. 9

Since between 80 and 85 percent of the cube's volume is below the surface of the water and between 12 and 16 cubic centimeters of the cube's volume is above the surface of the water, then 85-80=5% or 16-12=4 cubic centimeters of the volume is sometimes below and sometimes above the surface of the water. V*5%=4 cubic centimeters --> V=80 --> \(side=\sqrt[3]{80}=2\sqrt[3]{10}\approx{4.2}\).

Re: A certain cube floating in a bucket of water has between 80 [#permalink]
12 Sep 2013, 01:31

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: A certain cube floating in a bucket of water has between 80 [#permalink]
12 Sep 2013, 01:54

Antmavel wrote:

A certain cube floating in a bucket of water has between 80 and 85 percent of its volume below the surface of the water. If between 12 and 16 cubic centimeters of the cube's volume is above the surface of the water, then the length of a side of the cube is approximately

A. 4 B. 5 C. 7 D. 8 E. 9

1. 80% below water implies 20 % above water. 85% below water implies 15% above water 2. It is also given between 12 and 16 cu.cm above water. 3. So we can equate 20% to 16 cu.cm or 15% to 12 cu.cm. In either case 100% volume is 80 cu.cm 4. So length is cube root of 80 .

Re: A certain cube floating in a bucket of water has between 80 [#permalink]
08 Nov 2013, 22:38

1

This post received KUDOS

madn800 wrote:

Bunuel, how did you find value of cube root 10. How is it possible to compute such a value under exam conditions.

Hi,

Let us say you want to find out the cube root of 10. The cube of which number is immediately below 10? It is 2 because 2^3=8. Or you can see the cube of which number is immediately above 10? It is 3 because 3^3=27. So the cube root of 10 is between 2 and 3. You can further make it finer by seeing whether it is closer to 2^3 or 3^3. _________________

Re: A certain cube floating in a bucket of water has between 80 [#permalink]
07 Feb 2014, 01:27

Volume of cube of side s is s^3.

80% under water is 20% above water this implies

\(\frac{20}{100}*s^3 = 16\)

\(s^3=80\)

85% under water is 15% above water this implies

\(\frac{15}{100}*s^3 = 12\)

\(s^3 = 80\)

Now going to the answers if s=4 \(s^3 = 64\). closer to 80 a possible answer. if s=5 \(s^3 = 125\). too far from 80. hence A is answer. _________________

Re: A certain cube floating in a bucket of water has between 80 [#permalink]
29 Jul 2015, 18:09

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

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