Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

A certain fruit stand sold apples for $0.70 each and bananas [#permalink]
30 Sep 2010, 04:08

3

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

15% (low)

Question Stats:

79% (02:23) correct
21% (01:58) wrong based on 247 sessions

A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase ?

Re: help me to solve it..... [#permalink]
30 Sep 2010, 04:22

1

This post received KUDOS

Expert's post

pzazz12 wrote:

A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase ?

A. 10 B. 11 C. 12 D. 13 E. 15

Given: 0.7b+0.5a=6.3 Question: a+b=?

0.7a+0.5b=6.3 --> 7a+5b=63. After some trial and error you'll get that only two integer pairs of (a,b) satisfy this equation: (9,0) and (4,7) as we are told that "a customer purchased both apples and bananas" then the first pair is out and we'll have: a=4 and b=7 --> a+b=11.

Re: help me to solve it..... [#permalink]
30 Sep 2010, 18:49

4

This post received KUDOS

pzazz12 wrote:

A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase ?

A. 10 B. 11 C. 12 D. 13 E. 15

Without calculating anything in paper you could approach this problem.

Know -- Some multiple of 7 + Some multiple of 5 should yield 63. To get to a some multiple of 5, we should ensure that a 3 or 8 (5+3) should be a multiple of 7.

63 is a direct multiple of 7, however in this case there won't be any bananas. Hence the next option is to look for a multiple of 7 that has 8 as the unit digit. 28 satisfies this hence no. of apples is 4 and no of bananas is 7 -- Answer 11 (B). -- 35 seconds straight. _________________

Support GMAT Club by putting a GMAT Club badge on your blog

Re: help me to solve it..... [#permalink]
01 Oct 2010, 04:06

Bunuel wrote:

pzazz12 wrote:

A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase ?

A. 10 B. 11 C. 12 D. 13 E. 15

Given: 0.7b+0.5a=6.3 Question: a+b=?

0.7a+0.5b=6.3 --> 7a+5b=63. After some trial and error you'll get that only two integer pairs of (a,b) satisfy this equation: (9,0) and (4,7) as we are told that "a customer purchased both apples and bananas" then the first pair is out and we'll have: a=4 and b=7 --> a+b=11.

Answer: B.

thank you, but can you explain me how this (9,0) and (4,7) to be solve...

Re: help me to solve it..... [#permalink]
01 Oct 2010, 04:49

1

This post received KUDOS

Expert's post

pzazz12 wrote:

Bunuel wrote:

pzazz12 wrote:

A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase ?

A. 10 B. 11 C. 12 D. 13 E. 15

Given: 0.7a+0.5b=6.3 Question: a+b=?

0.7a+0.5b=6.3 --> 7a+5b=63. After some trial and error you'll get that only two integer pairs of (a,b) satisfy this equation: (9,0) and (4,7) as we are told that "a customer purchased both apples and bananas" then the first pair is out and we'll have: a=4 and b=7 --> a+b=11.

Answer: B.

thank you, but can you explain me how this (9,0) and (4,7) to be solve...

Trial and error would be good for it, but here is another way:

7a+5b=63 --> 5b=63-7a --> 5b=7(9-a) --> 5b must be multiple of 7 --> b must be multiple of 7 --> b can not be 0 (as "a customer purchased both apples and bananas") or >14 (as 5b in this case would be more than $6.30), so b=7 --> a=4.

Re: help me to solve it..... [#permalink]
10 Dec 2010, 19:14

ezhilkumarank wrote:

pzazz12 wrote:

A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase ?

A. 10 B. 11 C. 12 D. 13 E. 15

Without calculating anything in paper you could approach this problem.

Know -- Some multiple of 7 + Some multiple of 5 should yield 63. To get to a some multiple of 5, we should ensure that a 3 or 8 (5+3) should be a multiple of 7.

63 is a direct multiple of 7, however in this case there won't be any bananas. Hence the next option is to look for a multiple of 7 that has 8 as the unit digit. 28 satisfies this hence no. of apples is 4 and no of bananas is 7 -- Answer 11 (B). -- 35 seconds straight.

i get some multipule of 5 and 7 make 63... but why the multiple of 7 with a 3 or 8?

Re: help me to solve it..... [#permalink]
10 Dec 2010, 23:01

1

This post received KUDOS

Expert's post

mmcooley33 wrote:

ezhilkumarank wrote:

pzazz12 wrote:

A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase ?

A. 10 B. 11 C. 12 D. 13 E. 15

Without calculating anything in paper you could approach this problem.

Know -- Some multiple of 7 + Some multiple of 5 should yield 63. To get to a some multiple of 5, we should ensure that a 3 or 8 (5+3) should be a multiple of 7.

63 is a direct multiple of 7, however in this case there won't be any bananas. Hence the next option is to look for a multiple of 7 that has 8 as the unit digit. 28 satisfies this hence no. of apples is 4 and no of bananas is 7 -- Answer 11 (B). -- 35 seconds straight.

i get some multipule of 5 and 7 make 63... but why the multiple of 7 with a 3 or 8?

ezhilkumarank means that as multiple of 5 ends with 5 or 0 then multiple of 7 must end with 8 or 3 in order their sum to end with 3 (63). There is another approach in my previous post.

Re: A certain fruit stand sold apples for $0.70 [#permalink]
12 Dec 2010, 04:30

1

This post received KUDOS

Expert's post

ajit257 wrote:

A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase? A. 10 B. 11 C. 12 D. 13 E. 14

Is there a faster way to do these problems other than brute force ?

Re: help me to solve it..... [#permalink]
21 Dec 2010, 15:58

3

This post received KUDOS

Maybe it could be of any help to realise that

0.7y + 0.5x = 6.3 is a straight line, we want the 'y' on the left side, rewriting gives: 7y + 5x = 63 y = 9 - (5/7)x

Almost instantly you should see that the right term (5/7) can only be an integer if X is either 7, 14, 28 and so forth. Ruling out fourteen we only have 7 left which gives 9-5 = 4 +7 fruits. _________________

A certain fruit stand sold apples for $ 0.7 each and bananas for $0.5 each. If a customer purchased both apples and bananas from the stand for a total of $6.3, what total number of apples and bananas did the customer purchase?

A) 10

B) 11

C) 12

D) 13

E) 14

Relatively easy question, but I am struggling to solve.

Let say x be the number of apples and y be the number of bananas

0.7x + 0.5y = 6.3 -------------------------(1)

But how can this be solved if we don't have any other data in the question? _________________

A certain fruit stand sold apples for $ 0.7 each and bananas for $0.5 each. If a customer purchased both apples and bananas from the stand for a total of $6.3, what total number of apples and bananas did the customer purchase?

A) 10

B) 11

C) 12

D) 13

E) 14

Relatively easy question, but I am struggling to solve.

Let say x be the number of apples and y be the number of bananas

0.7x + 0.5y = 6.3 -------------------------(1)

But how can this be solved if we don't have any other data in the question?

Merging similar topics. Please ask if anything remains unclear. _________________

Re: help me to solve it..... [#permalink]
03 Jun 2012, 06:09

Expert's post

Mackieman wrote:

Maybe it could be of any help to realise that

0.7y + 0.5x = 6.3 is a straight line, we want the 'y' on the left side, rewriting gives: 7y + 5x = 63 y = 9 - (5/7)x

Almost instantly you should see that the right term (5/7) can only be an integer if X is either 7, 14, 28 and so forth. Ruling out fourteen we only have 7 left which gives 9-5 = 4 +7 fruits.

This is really fast, even though trial and error is also a good strategy _________________

Re: A certain fruit stand sold apples for $0.70 each and bananas [#permalink]
12 Sep 2013, 09:08

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Re: A certain fruit stand sold apples for $0.70 each and bananas [#permalink]
17 Dec 2013, 02:46

pzazz12 wrote:

A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase ?

A. 10 B. 11 C. 12 D. 13 E. 15

He buys both, and the only combination of multiples of 5 and 7 that end in the single digit 3 is the single digits of the respective multiples ending in 8 and 5, which means 28 = 4*7 for bananas, and 7*5 = 35 for apples.. From here you can simply just add a decimal inbetween so that the restriction is upheld.

4 bananas and 7 apples gives us 11 fruits.

gmatclubot

Re: A certain fruit stand sold apples for $0.70 each and bananas
[#permalink]
17 Dec 2013, 02:46

It’s been a long time, since I posted. A busy schedule at office and the GMAT preparation, fully tied up with all my free hours. Anyways, now I’m back...

Ah yes. Funemployment. The time between when you quit your job and when you start your MBA. The promised land that many MBA applicants seek. The break that every...

It is that time of year again – time for Clear Admit’s annual Best of Blogging voting. Dating way back to the 2004-2005 application season, the Best of Blogging...