Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
It appears that you are browsing the GMAT Club forum unregistered!
Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club
Registration gives you:
Tests
Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.
Applicant Stats
View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more
Books/Downloads
Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
A certain league has four divisions. The respective [#permalink]
16 Jul 2003, 03:59
3
This post received KUDOS
25
This post was BOOKMARKED
00:00
A
B
C
D
E
Difficulty:
95% (hard)
Question Stats:
44% (03:18) correct
56% (09:07) wrong based on 273 sessions
A certain league has four divisions. The respective divisions had 9, 10, 11, and 12 teams qualify for the playoffs. Each division held its own double-elimination tournament -- where a team is eliminated from the tournament upon losing two games -- in order to determine its champion. The four division champions then played in a single-elimination tournament -- where a team is eliminated upon losing one game -- in order to determine the overall league champion. Assuming that there were no ties and no forfeits, what is the maximum number of games that could have been played in order to determine the overall league champion?
AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993
Re: A certain league has four divisions. The respective [#permalink]
03 Mar 2014, 21:18
15
This post received KUDOS
Expert's post
6
This post was BOOKMARKED
PareshGmat wrote:
manpreetsingh86 wrote:
AkamaiBrah wrote:
A certain league has four divisions. The respective divisions had 9, 10, 11, and 12 teams qualify for the playoffs. Each division held its own double-elimination tournament -- where a team is eliminated from the tournament upon losing two games -- in order to determine its champion. The four division champions then played in a single-elimination tournament -- where a team is eliminated upon losing one game -- in order to determine the overall league champion. Assuming that there were no ties and no forfeits, what is the maximum number of games that could have been played in order to determine the overall league champion?
(A) 79 (B) 83 (C) 85 (D) 87 (E) 88
Let's name the teams in group 1 as 1,2,3,4,5,6,7,8,9.
Case 1; team1 played with every other team and won all of its matches. so total number of matchs =8 case 2: team2 , played with team 3,4,5,6,7,8,9 and won all of its matches. total number of matches =7 after case 1 and case 2 we have only two teams remaining in the group1 which are team 1 and team 2. Now since question asks us for the maximum no. of matches. Therefore we must include the extra case in which team 2 defeated team 1. Now both team 2 and team 1 have 1 loss each. Now in the final match, we will found out about the eventual winner in group 1. maximum no. of matches in group 1 are 8+7+1(in which team2 defeated team1) + 1 ( final) =17
Similarly in group 2 we have 9 + 8 +1 +1 =19 group 3 = 10+9+1+1 =21 group 4 = 11+10+1+1=23
After this we will have 4 winner from each group. lets name them as w1,w2,w3,w4 Let's assume w1 won all of its matches from the remaining three teams and eventually emerged as a winner. Therefore total matches among four winners=3
Therefore maximum total no. of matches played are 17+19+21+23+3=83
How long it took to solve this? Its taking a lot of time for me
Actually solving the problem doesn't take very long. Think of it this way:
We need to keep track of losses. Let's focus on those and forget about the wins. Every time a game is played, someone loses. You can give at most 2 losses to a team since after that it is out of the tournament. Consider the division which has 9 teams. What happens when 18 games are played? There are 18 losses and each team gets 2 losses (you cant give more than 2 to a team since it gets kicked out after 2 losses) so all are out of the tournament. But we need a winner so we play only 17 games so that the winning team get only 1 loss.
Similarly, the division with 10 teams can have at most 2*10 - 1 = 19 games. The division with 11 teams can have at most 2*11 - 1 = 21 games. The division with 12 teams can have at most 2*12 - 1 = 23 games. This totals up to 80 games (note that the average of 17, 19, 21 and 23 will be 20 so the sum will be 4*20 = 80).
Now you have 4 teams. 1 loss gets a team kicked out. If you have 3 games, there are 3 losses and 3 teams are kicked out. You have a final winner! Hence the total number of games = 80 + 3 = 83 _________________
Re: A certain league has four divisions. The respective [#permalink]
27 Feb 2014, 13:30
3
This post received KUDOS
AkamaiBrah wrote:
A certain league has four divisions. The respective divisions had 9, 10, 11, and 12 teams qualify for the playoffs. Each division held its own double-elimination tournament -- where a team is eliminated from the tournament upon losing two games -- in order to determine its champion. The four division champions then played in a single-elimination tournament -- where a team is eliminated upon losing one game -- in order to determine the overall league champion. Assuming that there were no ties and no forfeits, what is the maximum number of games that could have been played in order to determine the overall league champion?
(A) 79 (B) 83 (C) 85 (D) 87 (E) 88
Let's name the teams in group 1 as 1,2,3,4,5,6,7,8,9.
Case 1; team1 played with every other team and won all of its matches. so total number of matchs =8 case 2: team2 , played with team 3,4,5,6,7,8,9 and won all of its matches. total number of matches =7 after case 1 and case 2 we have only two teams remaining in the group1 which are team 1 and team 2. Now since question asks us for the maximum no. of matches. Therefore we must include the extra case in which team 2 defeated team 1. Now both team 2 and team 1 have 1 loss each. Now in the final match, we will found out about the eventual winner in group 1. maximum no. of matches in group 1 are 8+7+1(in which team2 defeated team1) + 1 ( final) =17
Similarly in group 2 we have 9 + 8 +1 +1 =19 group 3 = 10+9+1+1 =21 group 4 = 11+10+1+1=23
After this we will have 4 winner from each group. lets name them as w1,w2,w3,w4 Let's assume w1 won all of its matches from the remaining three teams and eventually emerged as a winner. Therefore total matches among four winners=3
Therefore maximum total no. of matches played are 17+19+21+23+3=83
Re: A certain league has four divisions. The respective [#permalink]
22 Jul 2014, 21:14
1
This post received KUDOS
Expert's post
SachinWordsmith wrote:
Thanks for the Reply Karishma. I follow your posts and your explanations are top notch.
If I went with the same logic, the answer would be 4 lesser (eliminating the number of games by the group winners lost in the Prelims) = 79 Games.
Can I generalize and use the above presented logic for say, a single elimination ( 1 Loss only) or triple elimination (3 Losses) format too?
Yes, you are correct. 4 fewer games is all you can afford.
Whether you can generalize will depend on the question. If the question remains the same: In case of a single loss elimination, there will be fixed number of games which will be played so there will be no maximum - minimum. Every game will have a loss and will eliminate exactly one team. In case of 3 loss elimination format, the qualifying team will not suffer any losses if we want to minimize the number of games and it will suffer 2 losses in case we want to maximize the number of games. _________________
As for divisional games: a minus is given for losing a game.
the 9-team division) lets count minuses; 8 teams can have 2 minuses and one (a champion) can have 1 minus. Total 17 minuses.
the 10-team division) lets count minuses; 9 teams can have 2 minuses and one (a champion) can have 1 minus. Total 19 minuses.
the 11-team division) lets count minuses; 10 teams can have 2 minuses and one (a champion) can have 1 minus. Total 21 minuses.
the 12-team division) lets count minuses; 11 teams can have 2 minuses and one (a champion) can have 1 minus. Total 23 minuses.
After that, four teams remained. I assume that when 3 teams can have 1 minus and the overall champion has none. Total 3 minuses.
Overall, there can be 83 minuses. Tus, it is B.
Very nicely done. This is correct and a fine approach to the problem. _________________
Best,
AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993
Re: A certain league has four divisions. The respective [#permalink]
26 Feb 2014, 03:04
Hello from the GMAT Club BumpBot!
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________
Re: A certain league has four divisions. The respective [#permalink]
03 Mar 2014, 20:48
manpreetsingh86 wrote:
AkamaiBrah wrote:
A certain league has four divisions. The respective divisions had 9, 10, 11, and 12 teams qualify for the playoffs. Each division held its own double-elimination tournament -- where a team is eliminated from the tournament upon losing two games -- in order to determine its champion. The four division champions then played in a single-elimination tournament -- where a team is eliminated upon losing one game -- in order to determine the overall league champion. Assuming that there were no ties and no forfeits, what is the maximum number of games that could have been played in order to determine the overall league champion?
(A) 79 (B) 83 (C) 85 (D) 87 (E) 88
Let's name the teams in group 1 as 1,2,3,4,5,6,7,8,9.
Case 1; team1 played with every other team and won all of its matches. so total number of matchs =8 case 2: team2 , played with team 3,4,5,6,7,8,9 and won all of its matches. total number of matches =7 after case 1 and case 2 we have only two teams remaining in the group1 which are team 1 and team 2. Now since question asks us for the maximum no. of matches. Therefore we must include the extra case in which team 2 defeated team 1. Now both team 2 and team 1 have 1 loss each. Now in the final match, we will found out about the eventual winner in group 1. maximum no. of matches in group 1 are 8+7+1(in which team2 defeated team1) + 1 ( final) =17
Similarly in group 2 we have 9 + 8 +1 +1 =19 group 3 = 10+9+1+1 =21 group 4 = 11+10+1+1=23
After this we will have 4 winner from each group. lets name them as w1,w2,w3,w4 Let's assume w1 won all of its matches from the remaining three teams and eventually emerged as a winner. Therefore total matches among four winners=3
Therefore maximum total no. of matches played are 17+19+21+23+3=83
How long it took to solve this? Its taking a lot of time for me _________________
Re: A certain league has four divisions. The respective [#permalink]
10 Mar 2014, 10:09
Dear Manpreet
I was applying the same trick but got confused in between.
Since, we allowed 3 matches between team 1 and team 2 in the first group, are you assuming that more than one match can be played between two teams as long as the team does not lose 2 matches in total?
Re: A certain league has four divisions. The respective [#permalink]
10 Mar 2014, 12:34
ShantnuMathuria wrote:
Dear Manpreet
I was applying the same trick but got confused in between.
Since, we allowed 3 matches between team 1 and team 2 in the first group, are you assuming that more than one match can be played between two teams as long as the team does not lose 2 matches in total?
Thanks & regards
yes, you are right. see the question asks us to find the maximum number of games that could have been played to determine the overall league champion. hence we go for the additional matches.
Re: A certain league has four divisions. The respective [#permalink]
10 Mar 2014, 21:32
1
This post was BOOKMARKED
The intuition is each team is eliminated after 2 losses. It has to lose 2 games and it can lose only 2 games. The winner loses only once or may not lose at all. But since maximum number of games is asked we will assume that the winner loses once.
Each loss corresponds to 1 game played.
For the 4 divisions the number of games played will be 2*8 + 1, 2*9 +1 , 2*10 +1 and 2*11+1= 17,19,21,23 resp= 80 total
Applying the same logic to the finals, the maximum number of games played will be 1*3 + 0=3
Re: A certain league has four divisions. The respective [#permalink]
22 Jul 2014, 03:17
Hi,
Could someone comment on how they would solve/approach it if the question were : What's the minimum number of games that could be played before a winner is determined?
Re: A certain league has four divisions. The respective [#permalink]
22 Jul 2014, 05:25
Expert's post
SachinWordsmith wrote:
Hi,
Could someone comment on how they would solve/approach it if the question were : What's the minimum number of games that could be played before a winner is determined?
Use the same logic as that used for maximum number of games. You know that each team must lose in at least 2 games (and at most 2 games). The only difference will be that the qualifying team will not lose any match to minimize the number of matches.
Now can you come up with the answer? _________________
Re: A certain league has four divisions. The respective [#permalink]
01 Apr 2015, 20:42
Hi,
I had a crazy thought. Here our goal is to maximize the matches. In Divison A we have 9 teams let them be a,b,c,d,e,f,g,h,i I let team "a" play with all other teams twice and lose every time. No. of matches=16 Similarly for b=14,c=12 etc. So we get a total of 72 matches in Group A alone.
Re: A certain league has four divisions. The respective [#permalink]
01 Apr 2015, 21:23
Expert's post
rmselva wrote:
Hi,
I had a crazy thought. Here our goal is to maximize the matches. In Divison A we have 9 teams let them be a,b,c,d,e,f,g,h,i I let team "a" play with all other teams twice and lose every time. No. of matches=16 Similarly for b=14,c=12 etc. So we get a total of 72 matches in Group A alone.
Here is what the question says: "Each division held its own double-elimination tournament -- where a team is eliminated from the tournament upon losing two games --"
When a loses its matches against b and c, it will be eliminated. It will not play any other game. It doesn't need to lose 2 matches against the same team for every team. _________________
Re: A certain league has four divisions. The respective [#permalink]
01 Apr 2015, 22:20
VeritasPrepKarishma wrote:
Actually solving the problem doesn't take very long. Think of it this way:
We need to keep track of losses. Let's focus on those and forget about the wins. Every time a game is played, someone loses. You can give at most 2 losses to a team since after that it is out of the tournament. Consider the division which has 9 teams. What happens when 18 games are played? There are 18 losses and each team gets 2 losses (you cant give more than 2 to a team since it gets kicked out after 2 losses) so all are out of the tournament. But we need a winner so we play only 17 games so that the winning team get only 1 loss.
Similarly, the division with 10 teams can have at most 2*10 - 1 = 19 games. The division with 11 teams can have at most 2*11 - 1 = 21 games. The division with 12 teams can have at most 2*12 - 1 = 23 games. This totals up to 80 games (note that the average of 17, 19, 21 and 23 will be 20 so the sum will be 4*20 = 80).
Now you have 4 teams. 1 loss gets a team kicked out. If you have 3 games, there are 3 losses and 3 teams are kicked out. You have a final winner! Hence the total number of games = 80 + 3 = 83
The “3 golden nuggets” of MBA admission process With ten years of experience helping prospective students with MBA admissions and career progression, I will be writing this blog through...
You know what’s worse than getting a ding at one of your dreams schools . Yes its getting that horrid wait-listed email . This limbo is frustrating as hell . Somewhere...