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A certain library assesses fines for overdue books as follow [#permalink]
03 Feb 2012, 07:32

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00:00

A

B

C

D

E

Difficulty:

25% (low)

Question Stats:

71% (01:29) correct
29% (00:44) wrong based on 103 sessions

A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.10. For each additional day that the book is overdue, the total fine is increased by $0.30 or doubled, whichever results in a lesser amount. What is the total for a book on the fourth day it is overdue?

A. $0.60 B. $0.70 C. $0.80 D. $0.90 E. $1.00

i approached it and got 1.00, but i cant understand why .70, which is B Someone care to show me how to approach this question thanks

Re: CERTAIN LIBRARY [#permalink]
03 Feb 2012, 07:36

3

This post received KUDOS

Expert's post

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manalq8 wrote:

A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.10. For each additional day that the book is overdue, the total fine is increased by $0.30 or doubled, whichever results in a lesser amount. What is the total for a book on the fourth day it is overdue?

A. $0.60 B. $0.70 C. $0.80 D. $0.90 E. $1.00

i approached it and got 1.00, but i cant understand why .70, which is B Someone care to show me how to approach this question thanks

Notice that, fines are already cumulative: "For each additional day that the book is overdue, the total fine is ..."

1st day fine - 0.1 2nd day fine - 0.1*2=0.2 (as doubling gives lower value) 3rd day fine - 0.2*2=0.4 (as doubling gives lower value) 4th day fine - 0.4+0.3=0.7 (as doubling gives higher value we add 0.3 this time)

Re: A certain library assesses fines for overdue books as follow [#permalink]
16 Jan 2013, 13:10

the total fine is increased by $0.30 or doubled, whichever results in a lesser amount - Keep the bolded phrases in mind .. it is quite confusing though .. Day 1 - $.10 Day 2- $.10 *2 or $.10+$.30 (Whichever results in a lesser amount), hence its $.20 Day 3 - $.20*2 or $.20+$.30, $.40 as its lesser Day 4 - $.40*2 or $.40+$.30, $.70 as this is lesser

Re: A certain library assesses fines for overdue books as follow [#permalink]
20 Apr 2013, 04:08

Expert's post

cyberjadugar wrote:

Hi,

I am little confused, since the question mentions that the total fine be increased by 0.3 or double, won't the question be solved in following way:

day 1 - 0.1 day 2 - 2*0.1 = 0.2 day 3 (total due = 0.3, day 1 + day 2) = 0.6 day 4 = 0.9

can anyone please point out the mistake in my understanding of the question?

Regards,

Total fine at the end of the 2nd day = 0.2. This means that the total fine, including the past fines, at the end of the second day is 0.2. Notice that 0.1 has already been accounted for.Thus, when you are calculating the total fine at the end of the third day, you refer to 0.2. Thus, total fine at the end of the third day is 0.2*2=0.4.

Re: Total fine of book on the 4th day of its overdue ? [#permalink]
23 Apr 2013, 02:17

This one's tricky for sure. Easy to fall for D. Here's the solution Day 1 = 0.1$ Day 2 ( Double or increase by 0.3$, chose the minimum one) Option1: Double -> 0.1*2= 0.2$ Option2: Increase by 0.3$ -> 0.1+0.3 = 0.4$ Minimum one: 0.2$ Day 3 Option1: Double -> 0.2*2=0.4$ Option2: Increase by 0.3$ -> 0.2+0.3=0.5$ Minimum one: 0.4$ Day 4 Option1: Double -> 0.4*2=0.8$ Option2: Increase by 0.3$ -> 0.4+0.3=0.7$ Minimum one: 0.7$ hence the OA.

Re: A certain library assesses fines for overdue books as follow [#permalink]
19 Jun 2014, 23:47

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