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A certain military vehicle can run on pure Fuel X, pure Fuel Y, or any [#permalink]

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31 Jan 2009, 11:05

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A certain military vehicle can run on pure Fuel X, pure Fuel Y, or any mixture of X and Y. Fuel X costs $3 per gallon; the vehicle can go 20 miles on a gallon of Fuel X. In contrast, Fuel Y costs $5 per gallon, but the vehicle can go 40 miles on a gallon of Fuel Y. What is the cost per gallon of the fuel mixture currently in the vehicle’s tank?

(1) Using fuel currently in its tank, the vehicle burned 8 gallons to cover 200 miles.

(2) The vehicle can cover 7 and 1/7 miles for every dollar of fuel currently in its tank

Re: A certain military vehicle can run on pure Fuel X, pure Fuel Y, or any [#permalink]

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31 Jan 2009, 14:53

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This post received KUDOS

shobuj40 wrote:

A certain military vehicle can run on pure Fuel X, pure Fuel Y, or any mixture of X and Y. Fuel X costs $3 per gallon; the vehicle can go 20 miles on a gallon of Fuel X. In contrast, Fuel Y costs $5 per gallon, but the vehicle can go 40 miles on a gallon of Fuel Y. What is the cost per gallon of the fuel mixture currently in the vehicle’s tank?

1) Using fuel currently in its tank, the vehicle burned 8 gallons to cover 200 miles. 2) The vehicle can cover 7 and 1/7 miles for every dollar of fuel currently in its tank

D.

1) 20x + 40 (8-x) = 200. x = Fuel x and y = 8-x x = 6 y = 2. suff.

2) 20/3 (a) + 40/5 (1-a) = 50/7

a = 9/14 1-a = 5/14

fraction of $ for fuel x + fraction of $ for fuel y = 1 a = fraction of $ for fuel x 1-a = fraction of $ for fuel y

Re: A certain military vehicle can run on pure Fuel X, pure Fuel Y, or any [#permalink]

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01 Feb 2009, 22:04

GMAT TIGER wrote:

shobuj40 wrote:

A certain military vehicle can run on pure Fuel X, pure Fuel Y, or any mixture of X and Y. Fuel X costs $3 per gallon; the vehicle can go 20 miles on a gallon of Fuel X. In contrast, Fuel Y costs $5 per gallon, but the vehicle can go 40 miles on a gallon of Fuel Y. What is the cost per gallon of the fuel mixture currently in the vehicle’s tank?

1) Using fuel currently in its tank, the vehicle burned 8 gallons to cover 200 miles. 2) The vehicle can cover 7 and 1/7 miles for every dollar of fuel currently in its tank

D.

1) 20x + 40 (8-x) = 200. x = Fuel x and y = 8-x x = 6 y = 2. suff.

2) 20/3 (a) + 40/5 (1-a) = 50/7

a = 9/14 1-a = 5/14

fraction of $ for fuel x + fraction of $ for fuel y = 1 a = fraction of $ for fuel x 1-a = fraction of $ for fuel y

suff...

I'm sorry but I don't get the 2nd equation. Can you explain why 20/3(a) = fraction of $ for fuel x?

Re: A certain military vehicle can run on pure Fuel X, pure Fuel Y, or any [#permalink]

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23 Jul 2015, 10:34

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Re: A certain military vehicle can run on pure Fuel X, pure Fuel Y, or any [#permalink]

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21 Aug 2016, 02:37

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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