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A certain one-day seminar consisted of a morning session and [#permalink]
12 Nov 2009, 07:59

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00:00

A

B

C

D

E

Difficulty:

85% (hard)

Question Stats:

42% (01:35) correct
58% (00:47) wrong based on 192 sessions

A certain one-day seminar consisted of a morning session and an afternoon session. If each of the 128 people attending the seminar attended at least one of the two sessions, how many of the people attended the morning session only.

(1) 3/4 of the people attended both sessions (2) 7/8 of the people attended the after noon session

Re: One day seminar [#permalink]
12 Nov 2009, 08:22

6

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Expert's post

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A certain one-day seminar consisted of a morning session and an afternoon session. If each of the 128 people attending the seminar attended at least one of the two sessions, how many of the people attended the morning session only.

(1) 3/4 of the people attended both sessions (2) 7/8 of the people attended the after noon session

(1) 3/4 of 128 is 96. So we know that 96 people attended both seminars. If you draw Venn diagram you'll see that 96 is the intersection of the people who attended morning session and the evening session. This only tells that minimum # of people for the morning session is 96. Morning only could be from 0 to 32. Not sufficient.

(2) 7/8 of the people attended the after noon session=112 people. This directly tells that 112 attended after noon session, as each of the 128 people attending the seminar attended at least one of the two sessions hence rest of the people 16, must have been attending the morning session and not attending the evening, which IS only morning session attendant #.

Again on Venn diagram 112 would be: only afternoon + intersection of morning and afternoon, so the third part which is morning only would be: total-(Afternoon and intersection)=128-112=16.

Answer: B.

P.S. You can attach the file directly to the question, so that everyone see it on the page. _________________

Re: One day seminar [#permalink]
16 Aug 2011, 10:23

Bunuel wrote:

A certain one-day seminar consisted of a morning session and an afternoon session. If each of the 128 people attending the seminar attended at least one of the two sessions, how many of the people attended the morning session only. (1) 3/4 of the people attended both sessions (2) 7/8 of the people attended the after noon session

(1) 3/4 of 128 is 96. So we know that 96 people attended both seminars. If you draw Venn diagram you'll see that 96 is the intersection of the people who attended morning session and the evening session. This only tells that minimum # of people for the morning session is 96. Morning only could be from 0 to 32. Not sufficient.

(2) 7/8 of the people attended the after noon session=112 people. This directly tells that 112 attended after noon session, as each of the 128 people attending the seminar attended at least one of the two sessions hence rest of the people 16, must have been attending the morning session and not attending the evening, which IS only morning session attendant #.

Again on Venn diagram 112 would be: only afternoon + intersection of morning and afternoon, so the third part which is morning only would be: total-(Afternoon and intersection)=128-102=26.

Answer: B.

P.S. You can attach the file directly to the question, so that everyone see it on the page.

Dear bunuel with all respects here is my doubt

here is the method to cross check the answer in gmat both option do not contradict (i hope i am correct) according to A 3/4th = 96 people attended both session (morning and afternoon both) and ccording to B 16 (1/8th) people attended morning session now how come both the options are telling different no of people in morning session

one more thing what would be the answer if the question were how many of the people attended the morning session [highlight]only omitted[/highlight]

PS: had [only] not been in the question no one would have even posted this _________________

WarLocK _____________________________________________________________________________ The War is oNNNNNNNNNNNNN for 720+ see my Test exp here http://gmatclub.com/forum/my-test-experience-111610.html do not hesitate me giving kudos if you like my post.

Re: One day seminar [#permalink]
16 Aug 2011, 11:03

fluke wrote:

Warlock007 wrote:

Dear bunuel with all respects here is my doubt

here is the method to cross check the answer in gmat both option do not contradict (i hope i am correct). Yes, that's true.

according to A 3/4th = 96 people attended both session (morning and afternoon both) and according to B 16 (1/8th) people attended morning session. Morning session ONLY.

now how come both the options are telling different no of people in morning session. Well!!! Statement 1 is not telling us much about the morning session, except that at least 96 people were there for the morning session. St1 and St2 are telling two different things and both are correct and non-conflicting.

one more thing what would be the answer if the question were how many of the people attended the morning session [highlight]only omitted[/highlight] "C" would be the answer in that case.

PS: had [only] not been in the question no one would have even posted this

Dear Fluke were "only" not there then B would have been a straight away answer (why would we need St A) _________________

WarLocK _____________________________________________________________________________ The War is oNNNNNNNNNNNNN for 720+ see my Test exp here http://gmatclub.com/forum/my-test-experience-111610.html do not hesitate me giving kudos if you like my post.

Re: One day seminar [#permalink]
16 Aug 2011, 11:24

1

This post received KUDOS

1

This post was BOOKMARKED

Warlock007 wrote:

Dear Fluke were "only" not there then B would have been a straight away answer (why would we need St A)

Actually, just the reverse would be correct. Please see the attached picture.

Attachment:

Seminar_Morning_Afternoon.JPG [ 9.91 KiB | Viewed 5948 times ]

Morning Session Only = Grey Color = M Both (Morning Session+Afternoon) = Orange Color = M&A Afternoon Session Only = Yellow Color = A

Q: If M+M&A+A=128 M=?

St1: M&A=96 Not Sufficient.

St2: M&A+A=112 Now, we know M&A+A+M=128 M&A+A=112 So, M=16(Morning Session only) Sufficient.

Ans: "B"

****************************************************************************** Now, if the question were: How many people attended morning session, we are asked to find M+M&A

St1: M&A=96 Not Sufficient.

St2: M&A+A=112 Now, we can't find "M&A+M" using this information and the stem. Not Sufficient.

Together: We can find "A" and eventually "M&A+M". Sufficient.

Re: One day seminar [#permalink]
16 Aug 2011, 11:29

fluke wrote:

Warlock007 wrote:

Dear Fluke were "only" not there then B would have been a straight away answer (why would we need St A)

Actually, just the reverse would be correct. Please see the attached picture.

Attachment:

Seminar_Morning_Afternoon.JPG

Morning Session Only = Grey Color = M Both (Morning Session+Afternoon) = Orange Color = M&A Afternoon Session Only = Yellow Color = A

Q: If M+M&A+A=128 M=?

St1: M&A=96 Not Sufficient.

St2: M&A+A=112 Now, we know M&A+A+M=128 M&A+A=112 So, M=16(Morning Session only) Sufficient.

Ans: "B"

****************************************************************************** Now, if the question were: How many people attended morning session, we are asked to find M+M&A

St1: M&A=96 Not Sufficient.

St2: M&A+A=112 Now, we can't find "M&A+M" using this information and the stem. Not Sufficient.

Together: We can find "A" and eventually "M&A+M". Sufficient.

Ans: "C"

Bingooooooooooo

thanks a lot fluke _________________

WarLocK _____________________________________________________________________________ The War is oNNNNNNNNNNNNN for 720+ see my Test exp here http://gmatclub.com/forum/my-test-experience-111610.html do not hesitate me giving kudos if you like my post.

Re: A certain one-day seminar consisted of a morning session and [#permalink]
23 Oct 2013, 06:41

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Re: One day seminar [#permalink]
30 Oct 2013, 12:39

Bunuel wrote:

A certain one-day seminar consisted of a morning session and an afternoon session. If each of the 128 people attending the seminar attended at least one of the two sessions, how many of the people attended the morning session only.

(1) 3/4 of the people attended both sessions (2) 7/8 of the people attended the after noon session

(1) 3/4 of 128 is 96. So we know that 96 people attended both seminars. If you draw Venn diagram you'll see that 96 is the intersection of the people who attended morning session and the evening session. This only tells that minimum # of people for the morning session is 96. Morning only could be from 0 to 32. Not sufficient.

(2) 7/8 of the people attended the after noon session=112 people. This directly tells that 112 attended after noon session, as each of the 128 people attending the seminar attended at least one of the two sessions hence rest of the people 16, must have been attending the morning session and not attending the evening, which IS only morning session attendant #.

Again on Venn diagram 112 would be: only afternoon + intersection of morning and afternoon, so the third part which is morning only would be: total-(Afternoon and intersection)=128-102=26.

Answer: B.

P.S. You can attach the file directly to the question, so that everyone see it on the page.

Bunuel, Statement 2 says that 7/8 attended the afternoon session (i.e. 112 ppl). From these, we don't know how many attended afternoon only or morning + afternoon, hence how can we say for sure that 16 attended morning only?

Re: One day seminar [#permalink]
31 Oct 2013, 00:23

Expert's post

Skag55 wrote:

Bunuel wrote:

A certain one-day seminar consisted of a morning session and an afternoon session. If each of the 128 people attending the seminar attended at least one of the two sessions, how many of the people attended the morning session only.

(1) 3/4 of the people attended both sessions (2) 7/8 of the people attended the after noon session

(1) 3/4 of 128 is 96. So we know that 96 people attended both seminars. If you draw Venn diagram you'll see that 96 is the intersection of the people who attended morning session and the evening session. This only tells that minimum # of people for the morning session is 96. Morning only could be from 0 to 32. Not sufficient.

(2) 7/8 of the people attended the after noon session=112 people. This directly tells that 112 attended after noon session, as each of the 128 people attending the seminar attended at least one of the two sessions hence rest of the people 16, must have been attending the morning session and not attending the evening, which IS only morning session attendant #.

Again on Venn diagram 112 would be: only afternoon + intersection of morning and afternoon, so the third part which is morning only would be: total-(Afternoon and intersection)=128-102=26.

Answer: B.

P.S. You can attach the file directly to the question, so that everyone see it on the page.

Bunuel, Statement 2 says that 7/8 attended the afternoon session (i.e. 112 ppl). From these, we don't know how many attended afternoon only or morning + afternoon, hence how can we say for sure that 16 attended morning only?

Consider this: we are asked to find how many of the people attended the morning session only. So, we need to find {Morning} - {Both}. Now:

Re: One day seminar [#permalink]
31 Oct 2013, 03:43

Bunuel wrote:

Skag55 wrote:

Bunuel wrote:

A certain one-day seminar consisted of a morning session and an afternoon session. If each of the 128 people attending the seminar attended at least one of the two sessions, how many of the people attended the morning session only.

(1) 3/4 of the people attended both sessions (2) 7/8 of the people attended the after noon session

(1) 3/4 of 128 is 96. So we know that 96 people attended both seminars. If you draw Venn diagram you'll see that 96 is the intersection of the people who attended morning session and the evening session. This only tells that minimum # of people for the morning session is 96. Morning only could be from 0 to 32. Not sufficient.

(2) 7/8 of the people attended the after noon session=112 people. This directly tells that 112 attended after noon session, as each of the 128 people attending the seminar attended at least one of the two sessions hence rest of the people 16, must have been attending the morning session and not attending the evening, which IS only morning session attendant #.

Again on Venn diagram 112 would be: only afternoon + intersection of morning and afternoon, so the third part which is morning only would be: total-(Afternoon and intersection)=128-102=26.

Answer: B.

P.S. You can attach the file directly to the question, so that everyone see it on the page.

Bunuel, Statement 2 says that 7/8 attended the afternoon session (i.e. 112 ppl). From these, we don't know how many attended afternoon only or morning + afternoon, hence how can we say for sure that 16 attended morning only?

Consider this: we are asked to find how many of the people attended the morning session only. So, we need to find {Morning} - {Both}. Now:

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