A certain organization presents reward to some people... : GMAT Problem Solving (PS)
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# A certain organization presents reward to some people...

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A certain organization presents reward to some people... [#permalink]

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15 Oct 2012, 18:37
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A certain organization presents reward to some people. There are 3 kinds of reward that respectively are $125,$40, $15. If the total reward is$1,735, what is the least possible value of the number of the people who received reward?

a. 17
b. 22
c. 32
d. 47
e. 90

[Reveal] Spoiler:
A
[Reveal] Spoiler: OA

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10 Dec 2012, 23:11
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To get the minimum value, one must maximize the largest price: $125 $$\frac{1735}{125}=\frac{347}{25}=13rem.110$$ Note that $$13*125=1625$$ so we calculate the remaining reward $$40A + 15B = 110$$ Again to get minimum value, maximize the largest remaining reward: $$40$$ $$\frac{110}{40}=2rem.30$$ Note that $$40*2=80$$ so we calculate the remaining reward $$15B = 110 - 80 =30$$ $$\frac{30}{15}=2$$ Thus, 13 + 2 + 2 = 17 Answer: A _________________ Impossible is nothing to God. Director Status: Done with formalities.. and back.. Joined: 15 Sep 2012 Posts: 647 Location: India Concentration: Strategy, General Management Schools: Olin - Wash U - Class of 2015 WE: Information Technology (Computer Software) Followers: 47 Kudos [?]: 548 [3] , given: 23 Re: A certain organization presents reward to some people... [#permalink] ### Show Tags 15 Oct 2012, 19:55 3 This post received KUDOS 1 This post was BOOKMARKED aeros232 wrote: A certain organization presents reward to some people. There are 3 kinds of reward that respectively are$125, $40,$15. If the total reward is \$1,735, what is the least possible value of the number of the people who received reward?

a. 17
b. 22
c. 32
d. 47
e. 90

[Reveal] Spoiler:
A

from question :
1735= 125A + 40B +15C
Since we have 3 variables and only other information we can infer is that each of A, B and C should be non negative integer (>=0). Hence, we need to plug in numbers to find out.
Now since the question is asking for 'least' number of rewards, best approach to start with is -finding least 'possible' number of rewards - it can happen when every award is 125. So number of reward in this case 1735/125 = 13 + some remainder. hence ans must be greater than 14.

This gives us
1735 = 13*125 + 40B +15C
or 40B + 15C =110
or 8B + 3C =22
Do we have any combination for B and C that works for this? yes.. if B=C=2.
Hence total number of rewards = A+B+C=13+2+2 = 17

same is given in A.

At this point, some observations could also be made. There could be a doubt in mind, what if A=12 and B+C <5? but note, it is not possible because for every A reduced, difference (125) is to be filled by at least 4 of Bs and Cs (40 and 15 respectively). Second, none of the answer choices is below 17.

Hence Ans A it is.
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Re: A certain organization presents reward to some people... [#permalink]

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22 Jan 2015, 09:48
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Re: A certain organization presents reward to some people... [#permalink]

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04 Feb 2015, 09:08
To get the minimum number of people, we want to maximize the number of people receiving the highest award.

1735/125 = 13 remainder 110.
110/40 = 2 remainder 30.
30/15 = 2.

13 +2 +2 = 17.
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Re: A certain organization presents reward to some people... [#permalink]

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25 Jul 2016, 10:58
Hello from the GMAT Club BumpBot!

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Re: A certain organization presents reward to some people...   [#permalink] 25 Jul 2016, 10:58
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