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A certain roller coaster has 3 cars, and a passenger is [#permalink]
21 Sep 2004, 02:58
A certain roller coaster has 3 cars, and a passenger is equally likely to ride in any 1 of the 3 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the roller coaster 3 times, what is the probability that the passenger will ride in each of the 3 cars?
Ans: C. Can anyone explain why? I thought it's B.
If x > 0, then 1/[v(2x)+vx] =
Ans: D. Can't figure out why.
June 25, 1982, fell on a Friday. On which day of the week did June 25, 1987, fall? (Note:1984 was a leap year.)
there are 3 cars and the requirement is that the person rides in 3 different cars
When he rides for the first time it does not matter wihch car he rides So P of riding in any one car for the first time(because there are 3 choices now) is 3/3
Now when he rides second time there are still 3 cars but he should ride in any one of the two cars other than the first one (because there only 2 choices )
so P = 2/3
FInally there are still 3 cars but he can ride only in 1 because he has already used two cars so P = 1/3
Total number of Pb = 3 x 3 x 3= 9 (each time he has three options and he rides thrice)
Favorable deals = 3 x 2 x 1 (He has three options to use for the first and two for the next, three for the last).
Pb = 6/27 = 2/9
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