Hi,

Probability = (favorable cases)/(total number of cases)

Total number of ways in which a person can ride car = 3*3*3 = 27

(In first ride he has 3 options to sit, in second right again he has 3 seats available to sit and so on)

Number of favorable cases, i.e., when he rides on different cars;

He can choose seat car in 3 ways in his 1st ride.

He can choose seat car in 2 ways in his 2nd ride.

He can choose seat car in 1 ways in his 3rd ride.

So, 3*2*1 = 6 ways

Thus, probability of choosing different seats = 6/27 = 2/9

(C)

Regards,

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