A certain roller coaster has 3 cars, and a passenger is : Quant Question Archive [LOCKED]
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 17 Jan 2017, 22:59

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# A certain roller coaster has 3 cars, and a passenger is

Author Message
Intern
Joined: 08 Nov 2008
Posts: 38
Followers: 0

Kudos [?]: 27 [0], given: 0

A certain roller coaster has 3 cars, and a passenger is [#permalink]

### Show Tags

11 Dec 2008, 13:01
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A certain roller coaster has 3 cars, and a passenger is equally likely to ride in any 1 of the 3 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the roller coaster 3 times, what is the probability that the passenger will ride in each of the 3 cars?

A. 0
B. 1/9
C. 2/9
D. 1/3
E. 1
SVP
Joined: 29 Aug 2007
Posts: 2492
Followers: 67

Kudos [?]: 734 [0], given: 19

### Show Tags

11 Dec 2008, 13:34
gorden wrote:
A certain roller coaster has 3 cars, and a passenger is equally likely to ride in any 1 of the 3 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the roller coaster 3 times, what is the probability that the passenger will ride in each of the 3 cars?

A. 0
B. 1/9
C. 2/9
D. 1/3
E. 1

first car = it could be any one of the three
second car = it could be any one of the remaining two
third car = it is the remaining one.

p(first) = 1
p(second) = 2/3
p(third) = 1/3

so p(each of 3 cars) = 1 x 2/3 x 1/3 = 2/9
_________________

Gmat: http://gmatclub.com/forum/everything-you-need-to-prepare-for-the-gmat-revised-77983.html

GT

Re: cars   [#permalink] 11 Dec 2008, 13:34
Display posts from previous: Sort by